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Strike441 [17]
3 years ago
8

A scatter plot is shown how many outliners does the graph show

Mathematics
2 answers:
Anna007 [38]3 years ago
8 0
The graph is not attached:(
ozzi3 years ago
6 0

Answer:

True

Step-by-step explanation:

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Course challenge
krek1111 [17]

Answer:

x=36

Divide the corresponding side (16) by 4/7

3 0
2 years ago
Read 2 more answers
How can i solve 5.5x+32=57
vladimir1956 [14]
(57-32)➗5.5 =x

The problem is just flipped.
8 0
3 years ago
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The price of a $250 item after successive discounts of 20% and<br> 30% is?
Ivan

Answer:

The price of item after successive discounts are 20% and 30% is $140.

Step-by-step explanation:

The marked price of item is $250.

Two successive discounts are 20% and 30%.

Price of item after discounts of 20% is

250-\frac{20}{100}(250)=250-50=200

New price of item after first discount is $200.

Price of item after second discount, i.e., 30% is

200-\frac{30}{100}(200)=200-60=140

Therefore, the price of item after successive discounts are 20% and 30% is $140.

3 0
3 years ago
I need help please. Thanks!
Karolina [17]

Answer:

A

Step-by-step explanation:

We are given the function f and its derivative, given by:

f^\prime(x)=x^2-a^2=(x-a)(x+a)

Remember that f(x) is decreasing when f'(x) < 0.

And f(x) is increasing when f'(x) > 0.

Firstly, determining our zeros for f'(x), we see that:

0=(x-a)(x+a)\Rightarrow x=a, -a

Since a is a (non-zero) positive constant, -a is negative.

We can create the following number line:

<-----(-a)-----0-----(a)----->

Next, we will test values to the left of -a by using (-a - 1). So:

f^\prime(-a-1)=(-a-1-a)(-a-1+a)=(-2a-1)(-1)=2a+1

Since a is a positive constant, (2a + 1) will be positive as well.

So, since f'(x) > 0 for x < -a, f(x) increases for all x < -a.

To test values between -a and a, we can use 0. Hence:

f^\prime(0)=(0-a)(0+a)=-a^2

This will always be negative.

So, since f'(x) < 0 for -a < x < a, f(x) decreases for all -a < x < a.

Lasting, we can test all values greater than a by using (a + 1). So:

f^\prime(a+1)=(a+1-a)(a+1+a)=(1)(2a+1)=2a+1

Again, since a > 0, (2a + 1) will always be positive.

So, since f'(x) > 0 for x > a, f(x) increases for all x > a.

The answer choices ask for the domain for which f(x) is decreasing.

f(x) is decreasing for -a < x < a since f'(x) < 0 for -a < x < a.

So, the correct answer is A.

3 0
3 years ago
The Value that you insert into a function is know as the?
Tanzania [10]

Answer:

Step-by-step explanation:

Most commonly, that value would be the "independent variable."

We evaluate the function at that particular value of the independent variable.

7 0
3 years ago
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