Question

The masses of two heavenly bodies are 2×10‘16’ and 4×10 ‘22’ kg respectively and the distance between than is 30000km. find the gravitational force between them ? ans. 2.668× 10-9N​

Answer 1

$F = 5.93×10^{13}\:\text{N}$

Explanation:

Given:

$m_1= 2×10^{16}\:\text{kg}$

$m_2= 4×10^{22}\:\text{kg}$

$r = 30000\:\text{km} = 3×10^7\:\text{m}$

Using Newton's universal law of gravitation, we can write

$F = G\dfrac{m_1m_2}{r^2}$

$\:\:\:\:=(6.674×10^{-11}\:\text{N-m}^2\text{/kg}^2)\dfrac{(2×10^{16}\:\text{kg})(4×10^{22}\:\text{kg})}{(3×10^7\:\text{m})^2}$

$\:\:\:\:= 5.93×10^{13}\:\text{N}$