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sleet_krkn [62]
3 years ago
12

A laser on the South American plate takes a certain amount of time to reach a satellite and bounce back to Earth. Five years lat

er, the laser takes a little more time to reach the satellite and bounce back. What does this suggest about the South American plate?
A. Lasers can't tell us anything about tectonic plates.

B. The South American plate has not moved over time.

C. The South American Plate has moved over time.

D. The South American plate affects the speed of lasers.
Physics
2 answers:
loris [4]3 years ago
4 0

its c. i just got it right


tigry1 [53]3 years ago
3 0
I think the answer is B but the problem in this part is that the South American plate has moved over time. You see the difference?
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Answer:

Work is the energy transferred to or from an object via the application of force along a displacement.

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3 years ago
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How did mount st. Helen get its name
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2. A woman prevents a 3kg brick from falling by pressing it against a vertical wall. The coefficient of friction
Anettt [7]
<h3>Answer:</h3>

49 N

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of the brick as 3 kg
  • The coefficient of friction as 0.6

We are required to determine the force that must be applied by the woman so the brick does not fall.

  • We need to importantly note that;
  • For the brick not to fall the, the force due to gravity is equal to the friction force acting on the brick.
  • That is; Friction force = Mg

But; Friction force = μ F

Therefore;

μ F = mg

0.6 F = 3 × 9.8

0.6 F = 29.4

      F = 49 N

Therefore, she must use a force of 49 N

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3 years ago
The motion of a particle is described by the position function s(t) = 2t - 15t +33t+17,t&gt;0 , where is measured in seconds and
8090 [49]

The time when the particle is at rest is at 1.63 s or 3.36 s.

The velocity is positive at when the time of motion is at 0.

The total distance traveled in the first 10 seconds is 847 m.

<h3>When is a particle at rest?</h3>
  • A particle is at rest when the initial velocity of the particle is zero.

The time when the particle is at rest is calculated as follows;

s(t) = 2t³ - 15t² + 33t + 17

v = \frac{ds}{dt} = 6t^2 -30t + 33\\\\at \ rest, \ v = 0\\\\6t^2 - 30t + 33 = 0\\\\6(t- \frac{5}{2} )^2- \frac{9}{2} = 0\\\\t = 1.63\ s \ \ or \ 3.36 \ s

The velocity is positive at when the time of motion is as follows;

0.

The total distance traveled in the first 10 seconds is calculated as follows;

2(10)^3 - 15(10)^2 + 33(10) + 17 = 847 \ m

Learn more about motion of particles here: brainly.com/question/11066673

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Compaction: As the density of sedimentary rocks on edge of them are forced together through sediments.

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