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3 years ago

Describing Forms of Energy

Physics

1 answer:

Ber [7]3 years ago

6 0

Answer:

electrical energy-found in the flow of electrical charges

chemical energy-found in the bonds BTW atoms

thermal energy-found when internal energy is transferred

nuclear energy-found in the nucleus of an atom.

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What are wind and water erosion not likely to affect

zavuch27 [327]

Answer:

Tides, bodies of water

Explanation:

5 0

2 years ago

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In each cycle, a heat engine performs 710 J of work and exhausts 1480 J of heat. What is the thermal effiency?

Tomtit [17]

Answer:

32%

Explanation:

For a heat engine, efficiency is work out divided by heat in:

η = Wₒ / Qᵢ

Since energy is balanced, heat in is the sum of work out and heat out:

Qᵢ = Wₒ + Qₒ

Therefore:

η = Wₒ / (Wₒ + Qₒ)

Given Wₒ = 710 J and Qₒ = 1480 J:

η = 710 / (710 + 1480)

η = 0.32

The thermal efficiency is 32%.

6 0

3 years ago

6. Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast

nata0808 [166]

<h3>given:</h3>

first trip= 50 miles.

second trip= 300 miles.

his new time compared to the old time.

<h3>solution:</h3>

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

Speed = Distance/Time

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

= 100/x hr

Therefore, his new time compared with the old time was twice as much.

answer= b) twice as much

5 0

1 year ago

Sometimes the net force of an object is zero, this is when the forces are balanced. * 1 point True False

Degger [83]

Yes it is true because when the net force is 0 then there is no force

5 0

3 years ago

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Two satellites are in circular orbits around a planet that has radius 9.00×106 m. One satellite has mass 68.0 kg, orbital radius

olasank [31]

Answer:

v₂ = 5131.42 m/s

Explanation:

given,

radius of the planet = r₁ = 9.00×10⁶ m

mass of the satellite = m₁ = 68 Kg

orbital radius = r₁ = 8 x 10⁷ m

orbital speed = v₁ = 4800 m/s

mass of second satellite = m₂ = 84.0 kg

orbital radius = r₂ = 7.00×10⁷ m

orbital speed of second satellite = v₂ = ?

using orbital speed of satellite

$v = \sqrt{\dfrac{GM}{r}}$

so,

$v \alpha \dfrac{1}{\sqrt{r}}$

now,

$\dfrac{v_1}{v_2} =\sqrt{\dfrac{r_2}{r_1}}$

$\dfrac{v_2}{4800} =\sqrt{\dfrac{8\times 10^7}{7 \times 10^7}}$

v₂ = 5131.42 m/s

The orbital speed of second satellite is equal to v₂ = 5131.42 m/s

7 0

3 years ago