2 years ago

5Convert 1101 two to base 5

Mathematics

1 answer:

Lina20 [59]2 years ago

3 0

the answer is 23...........

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Question:Find the area of he trapezoid by decomposing it into other shapes.

Ad libitum [116K]

Answer:

D) 171 cm²

Step-by-step explanation:

You don’t actually need to decompose it. You could just do it as a trapezoid:

(15+23)/2=19

19x9=171

If you want to decompose it into 2 triangles and a rectangle:

10=15x9=135

1/2(3)(9)=13.5

1/2(5)(9)=22.5

135+13.5+22.5=171 also

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What principle will amount to $6000 if invested at 5.5% compounded monthly for 10 years?

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Answer:In 10 years, you will have $10,386.46

Step-by-step explanation:

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I need help with math if you don't know the answer get out of the question and don't answer it and give the wrong answer or some

velikii [3]

Answer:

Step-by-step explanation:

Frequency table for the height of the seedlings,

Height (in inches) Number of seedlings

$\frac{1}{2}$ 2

$\frac{3}{4}$ 4

$\frac{5}{8}$ 2

$\frac{7}{8}$ 2

Now we can draw the line plot as attached.

Average height of the seedlings = $\frac{2(\frac{1}{2})+4(\frac{3}{4})+2(\frac{5}{8})+2(\frac{7}{8})}{2+4+2+2}$

= $\frac{1+3+1.25+1.75}{10}$

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2 years ago

John's cell phone gives him 1250 minutes for $25. He used 1300 minutes. How much will his cell phone company bill him for? A) Si

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A cliff diver jumps from a cliff that is 96 feet above the water. His jump can be modeled by a quadratic equation, h= -16t(expon

ladessa [460]

Answer:

The diver will take 2.449 seconds to enter the water.

Step-by-step explanation:

We have been given that quadratic equation for the diver jumps is

$h=-16t^2+96$

We have to find the time taken for the diver to enter the water. When the diver enters the water, the height becomes zero.

$0=-16t^2+96\\\\16t^2=96\\\\t^2=6\\\\t=\sqrt6\\\\t=2.449\text{ seconds}$

Therefore, the diver will take 2.449 seconds to enter the water.

4 0

3 years ago

5Convert 1101 two to base 5​

5Convert 1101 two to base 5