Answer:
When extra energy is added
Explanation:
When the ball is released from rest and swings back towards your face, it will only pass closer to the end of the nose as per the initial conditions. However, when extra energy is added to the ball, it strikes the nose since its velocity and heights are increased. Therefore, the only condition under which the ball hits your nose is when extra energy is added to the system.
Answer:
450m
Explanation:
You would use the equation x-x0=0.5(v0+v)t as you have the time and velocities. x-x0(Change in position/displacement)=0.5(0+30)30. The distance will be 450m.
Answer:
0.20 A
Explanation:
The current in the wire is given by Ohm's law:

where
I is the current
V is the voltage
R is the resistance
In this problem,
V = 3.0 V is the voltage
is the resistance
Substituting into the formula,

Answer:
Explanation:
Person suffering from myopia is unable to see objects beyond 50 cm because far point of his vision is 50 cm . He requires a concave lens
( diverging lens ) to correct his vision .
After using the lens ,
ray of light coming from far off place will appear to be coming from 50 cm after refraction through lens so it will be focused on retina .
object distance u = ∝
image distance v = - 50 cm
focal length f = ?
1 / v - 1 / u = 1 /f
- 1 / 50 - 1 / ∝ = 1 / f
- 1 / 50 = 1 / f
f = - 50 cm
focal length is negative so len is concave.
He requires concave lens of focal length 50 cm .
Answer:
Let the mass of the book be "m", acceleration due to gravity be "g", velocity be "v" and height be "h".
Now if we are holding a book at a certain height (h), <em><u>the potential energy will be maximum which is equal to mass× acceleration due to gravity× height (= mgh)</u>.</em>
(Remember: kinetic energy =0)
Now we consider that the book is dropped, in this case a force will act downward towards the centre of the earth, <em><u>Force= mass× acceleration due to gravity (F=mg)</u></em>. It is equal to the weight of the book.
While the book is falling, the potential energy stored in the book converts into kinetic energy and strikes the floor with <em><u>the maximum kinetic energy= (1/2)×mass×velocity² (=1/2mv²)</u>.</em>
(Remember: kinetic energy=0)
Due to this process the whole energy is conserved.
As the potential energy decreases kinetic energy increases.