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qaws [65]
3 years ago
8

A trap-jaw ant snaps its mandibles shut at very high speed, good for catching small prey. But these ants also slam their mandibl

es into the ground; the resulting force can launch the ant into the air for a quick escape. If a 12 mg ant hits the ground with an average force of 47 mN for a time of 0.13 ms, at what speed will it leave the ground?
Physics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

FInal speed (v) = 0.509 m/s (Approx)

Explanation:

Given:

Mass of ant (m) = 12 mg

Force (f) = 47 N

Time taken (t) = 0.13 ms

Find:

FInal speed (v) = ?

Computation:

Initial velocity (u) = 0

Impulse = change in momentum

Force × TIme = change in momentum

47 × 0.13 = mv - mu

6.11 = 12 (V)

FInal speed (v) = 0.509 m/s (Approx)

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This also tells us that matter is mostly empty space ! 

-- In Bohr's model of the atom, he described the whole thing very much
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We learned later that it's impossible to talk about things like "how big is
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5 0
3 years ago
Which statement describes oneScientists have changed the model of the atom as they have gathered new evidence. One of the atomic
GuDViN [60]

Answer:

el continuo movimiento

Explanation:

5 0
3 years ago
A girl is sitting in a sled sliding horizontally along some snow (there is friction present).
Over [174]

Answer:

159 N

Explanation:

The force of friction, Fr is a product of coefficient of feiction and the normal force. Therefore, Fr=uN where N is the normal force and u is coefficient of friction. Here, we have two coefficients of friction but since it is sliding, then we use coefficient of kinetic energy. Substituting 0.25 for u and 636 N for N then

Fr=0.25*636=159 N

Therefore, the force of friction is equivalent to 159 N

4 0
3 years ago
Looking at group 2 on the periodic table which of these elements probably has the lowest ionic radius
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I think the answer is Helium.

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3 years ago
When does PE equal KE?
dybincka [34]
PE equals KE when KE is 50%. 

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Hope I helped. :)
4 0
3 years ago
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