Question

If a nichrome wire has a resistance of 15Ω and is connected across the terminals of a 3.0 V flashlight battery, how much current is in the wire?
1.0 amps
5.0 amps
7.5 amps
0.20 amps

Answer 1

Answer:

0.20 A

Explanation:

The current in the wire is given by Ohm's law:

$I=\frac{V}{R}$

where

I is the current

V is the voltage

R is the resistance

In this problem,

V = 3.0 V is the voltage

$R=15 \Omega$ is the resistance

Substituting into the formula,

$I=\frac{3.0 V}{15 \Omega}=0.20 A$