Question

A well is to be dug at the location in the diagram. Use the diagram for the parts.

Answer 1

Answer:

$y = \frac{1}{6}x - 5$

Step-by-step explanation:

The equation that represents the road can be written as $y = mx + b$

Find, m = slope, and b = y-intercept of the line.

Using two points on the line, (-6, -6) and (6, -4), find the slope:

$slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-4 -(-6)}{6 -(-6)} = \frac{2}{12} = \frac{1}{6}$

Substitute x = -6, y = -6, and m = ⅙ into $y = mx + b$ to find b.

$-6 = \frac{1}{6}(-6) + b$

$-6 = -1 + b$

Add 1 to both sides

$-6 + 1 = b$

$-5 = b$

Substitute m = ⅙, and b = -5 into $y = mx + b$.

✅The equation that represents the road would be:

$y = \frac{1}{6}x + (-5)$

$y = \frac{1}{6}x - 5$