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VladimirAG [237]
3 years ago
11

4720 kJ of energy are supplied to a material in order to raise its temperature by 65K. If the specific heat capacity of the mate

rial is 2730 J kg-1 K-1 then what is its mass?
Chemistry
1 answer:
algol [13]3 years ago
6 0

Answer : The correct answer for mass of material = 26.6 Kg

Given : Q = 4720 KJ

Change in Temperature ( ΔT ) = 65 K

Specific heat capacity of material ( c) = 2730 \frac{J}{Kg* K}

The relation between Q , ΔT , c and m are related by following formula :

Q = m* c*ΔT ,

where Q = Heat or energy absorbed or released

m = mass , c = specific heat ,ΔT = change in Temperature

Plugging value in heat formula :

4720 KJ = m * 2730 \frac{J}{Kg * K} * 65 K

4720 KJ = m * 177450 \frac{J}{Kg}

[[Converting 177450 \frac{J}{Kg}  to \frac{KJ}{Kg}

177450 \frac{J}{Kg}  * \frac{1 KJ}{1000 J}  = 177.450 \frac{KJ}{Kg} ]]

Dividing both side by 177.450 \frac{KJ}{Kg}

\frac{4720 KJ}{177.450 \frac{KJ}{Kg}}  = m * \frac{177.450\frac{KJ}{Kg} }{177.450\frac{KJ}{Kg} }

m = 26.6 Kg

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A sample of sodium reacts completely with 0.284 kg of chlorine, forming 468 g of sodium chloride. What mass of sodium reacted?
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Answer:

mass of sodium reacted is 184.1 g

Explanation:

  • Na + Cl → NaCl

mass Na = X = ?

∴ mass NaCl = 468 g

∴ mass Cl = 0.248 g

∴ molar mass NaCl = 58.44 g/mol

∴ atomic mass Cl = 35.453 a.m.u

∴ atomic mass Na = 22.989 a.m.u

⇒ moles Na = (X gNa)*(mol Na/22.989 g) = X/22.989 mol Na

⇒ mass NaCl = (X/22.989 mol Na)*(mol NaCl/mol Na)*(58.44 gNaCl/mol NaCl) = 468 g NaCl

clearing "X":

⇒ ((58.44)(X))/(22.989) = 468 g

⇒ X = 184.1 g = mass Na reacted

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3 years ago
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Explanation:

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We are required to determine whether the triangle is right angle.

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In this case;

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