Answer:
Acid + Base -------> Salt + Water
Explanation:
The reaction between an acid and bases is called a neutralization reaction. The result of the reaction is salt and water. For example, when hydrochloric acid(acid) and sodium hydroxide(base) react they form sodium chloride(salt) and water. Also, heat is evolved.
Example:
HCl + NaOH ----------> NaCl + H2O
HCl is hydrochloric acid.
NaOH is sodium hydroxide which is a base.
NaCl is sodium chloride which is a salt.
H2O is water.
Are found along volcanic island arcs
Answer:
Explanation:
<u>1) Mass of carbon (C) in 2.190 g of carbon dioxide (CO₂)</u>
- atomic mass of C: 12.0107 g/mol
- molar mass of CO₂: 44.01 g/mol
- Set a proportion: 12.0107 g of C / 44.01 g of CO₂ = x / 2.190 g of CO₂
x = (12.0107 g of C / 44.01 g of CO₂ ) × 2.190 g of CO₂ = 0.59767 g of C
<u />
<u>2) Mass of hydrogen (H) in 0.930 g of water (H₂O)</u>
- atomic mass of H: 1.00784 g/mol
- molar mass of H₂O: 18.01528 g/mol
- proportion: 2 × 1.00784 g of H / 18.01528 g of H₂O = x / 0.930 g of H₂O
x = ( 2 × 1.00784 g of H / 18.01528 g of H₂O) × 0.930 g of H₂O = 0.10406 g of H
<u>3) Mass of oxygen (O) in 1.0857 g of pure sample</u>
- Mass of O = mass of pure sample - mass of C - mass of H
- Mass of O = 1.0857 g - 0.59767 g - 0.10406 = 0.38397 g O
Round to four decimals: Mass of O = 0.3840 g
<u>4) Mole calculations</u>
Divide the mass in grams of each element by its atomic mass:
- C: 0.59767 g / 12.0107 g/mol = 0.04976 mol
- H: 0.10406 g / 1.00784 g/mol = 0.10325 mol
- O: 0.3840 g / 15.999 g/mol = 0.02400 mol
<u>5) Divide every amount by the smallest value (to find the mole ratios)</u>
- C: 0.04976 mol / 0.02400 mol = 2.07 ≈ 2
- H: 0.10325 mol / 0.02400 mol = 4.3 ≈ 4
- O: 0.02400 mol / 0.02400 mol = 1
Thus the mole ratio is 2 : 4 : 1, and the empirical formula is:
Answer:
Brhrhrhrhhrhrhry hehhehdhdhhehehebebebbendjkdjdjfjcjbsksoejejjdnd
Explanation:
Dmdmsnsjsbbs नमस्कार ndjdjdjdjdjdjdjdhdjdjd ndndjdhdjdjdj ndjdjdjdjdjdjdjdhdjdjd ndndjd
There are many compounds which contain triple bonds between two atoms. Few of the are as follow,
Nitrogen Molecule:
N₂ or :N≡N:
Cyanide Ion:
CN⁻ or [:C≡N:]⁻
Alkynes:
R-C≡C-R
Carbon Monoxide:
CO or :C≡O:
Among given compounds Alkynes belong to a class of unsaturated hydrocarbons. The carbon atom in alkyne is sp hybridized. These unsaturated hydrocarbons have their own characteristic chemical properties.