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VladimirAG [237]
3 years ago
11

4720 kJ of energy are supplied to a material in order to raise its temperature by 65K. If the specific heat capacity of the mate

rial is 2730 J kg-1 K-1 then what is its mass?
Chemistry
1 answer:
algol [13]3 years ago
6 0

Answer : The correct answer for mass of material = 26.6 Kg

Given : Q = 4720 KJ

Change in Temperature ( ΔT ) = 65 K

Specific heat capacity of material ( c) = 2730 \frac{J}{Kg* K}

The relation between Q , ΔT , c and m are related by following formula :

Q = m* c*ΔT ,

where Q = Heat or energy absorbed or released

m = mass , c = specific heat ,ΔT = change in Temperature

Plugging value in heat formula :

4720 KJ = m * 2730 \frac{J}{Kg * K} * 65 K

4720 KJ = m * 177450 \frac{J}{Kg}

[[Converting 177450 \frac{J}{Kg}  to \frac{KJ}{Kg}

177450 \frac{J}{Kg}  * \frac{1 KJ}{1000 J}  = 177.450 \frac{KJ}{Kg} ]]

Dividing both side by 177.450 \frac{KJ}{Kg}

\frac{4720 KJ}{177.450 \frac{KJ}{Kg}}  = m * \frac{177.450\frac{KJ}{Kg} }{177.450\frac{KJ}{Kg} }

m = 26.6 Kg

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