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4 years ago

After raining when do rain drops dry away easily on a cloudy day or on a sunny day? explain

Chemistry

2 answers:

padilas [110]4 years ago

4 0

I would tend to think that the amount of sunlight reaching the water is irrelevant.

The color of the surface that the water lies on is more important. A black, matte

surface absorbs more infrared radiation than a light-colored, reflective surface.

Paladinen [302]4 years ago

3 0

On a sunny day the temperature might be above 40°C which will cause the water to vaporize quicker as if it were cloudy and colder

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I have 345mL of a 1.5M NaCl solution. If I boil the water until the volume of the solution is 250mL, what will the molarity of t

Karo-lina-s [1.5K]

Answer is
C. 2.07 M

For explanation

M1V1 = M2V2

M2 = (M1V1)/V2

M2 = (1.5M x 345ml) / 250 ml

:. M2 = 2.07 M

8 0

3 years ago

In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10%

nexus9112 [7]

First, let us calculate the moles of solute or sodium bicarbonate is in the 1 ml solution.

<span>moles = 1 mL * (1 g / 9 mL) = 0.11 moles</span>

The molar mass of sodium bicarbonate is 84 g/mol, therefore the mass is:

mass = 0.11 moles * 84 g/mol

6 0

3 years ago

A chemist uses hot hydrogen gas to convert chromium(III) oxide to

Darya [45]

Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$

Explanation:

The reaction equation for given reaction is as follows.

$Cr_{2}O_{3} + 3H_{2} \rightarrow 2Cr + 3H_{2}O$

Here, 1 mole of $Cr_{2}O_{3}$ reacts with 3 moles of $H_{2}$ .

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide $(Cr_{2}O_{3})$ is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of $Cr_{2}O_{3}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol$

Now, moles of $H_{2}$ .given by 0.5 mol of $Cr_{2}O_{3}$ is calculated as follows.

$0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}$

As molar mass of $H_{2}$ is 2.016 g/mol. Therefore, mass of $H_{2}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g$

Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$ .

7 0

3 years ago

What is the study of blood cells

LiRa [457]

Answer:

Hematology is the study of blood

Explanation:

The cellular component consists of three major cell types, all of which arise from hematopoietic stem cells located primarily in the bone marrow: red blood cells (RBCs), white blood cells (WBCs), and platelets.

6 0

3 years ago

Which set of reagents will best convert 2,2-dimethylpropan-1-ol (neopentyl alcohol) to 4,4-dimethylpentan-2-ol

Sladkaya [172]

Answer:

SOCl2, Mg, CH3CHO, H3O^+

Explanation:

The reaction of the 2,2-dimethylpropan-1-ol with SOCl2 converts the alcohol to an alkyl halide. This now reacts with Mg metal to yield a Grignard reagent.

The Grignard reagent reacts with CH3CHO and acid to yield 4,4-dimethylpentan-2-ol as shown in the image attached to this answer.

6 0

3 years ago