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LiRa [457]
2 years ago
14

If the vertex of a parabola is (- 3, 4) and the parabola has a stretch of 3find the next two points on the parabola right the ve

rtex
Mathematics
1 answer:
Sindrei [870]2 years ago
7 0

Answer:

Step-by-step explanation:

Need help asap please

5 x 2 = what pls

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Given that g(x)=x+3 calculate g(-5)
hjlf

Note that -5 = x, plug in -5 for x

g(x) = x + 3

g(-5) = (-5) + 3

Simplify

g(-5) = -5 + 3

g(-5) = -2

g(-5) = -2 is your answer

~

6 0
3 years ago
Read 2 more answers
Help with this please.
Ivanshal [37]

Answer:

  • True
  • True

Step-by-step explanation:

This question asks you to compare the coordinates of the vertex of each function.

__

The vertex of the function is its minimum, the point where the graph stops decreasing and starts increasing. It is the lowest point on the graph.

<h3>f(x)</h3>

The vertex is (-4, -1). The minimum is -1, located at x = -4.

<h3>g(x)</h3>

The vertex is (1, -25). The minimum is -25, located at x = 1. We know this is the minimum because there are no g(x) values that are lower (more negative).

<h3>comparison</h3>

The minimum of f(x), -1, is greater than the minimum of g(x), -25. TRUE

The x-value of f(x) at its minimum, -4, is less than the x-value of g(x) at its minimum, 1. TRUE

8 0
2 years ago
Please help, whoever gets it right I will mark brainliest.
Pepsi [2]

Answer:

One and Four

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Please help me with this problem​
Rom4ik [11]

y=x^2 + x - 2

x + y = 1

Replace y in the second equation:

x + x^2 + x -2 = 1

Simplify:

x^2 + 2x -2 = 1

Subtract 1 from both sides:

x^2 + 2x -3 = 0

Factor:

(x-1) (x+3) = 0

Solve for both x's:

x = 1 and x = -3

Now replace x in the second equation and solve for y using both x values:

1 + y = 1, y = 0

-3 + y = 1, y = 4

Now you have (1,0) and (-3,4) as solutions for (x,y)

XY = x times y:

1 x 0 = 0

-3 x 4 = -12

The answer would be -12

6 0
3 years ago
What is the are of a hexagon with a radius of 5 inches?
xxTIMURxx [149]
The area of a hexagon with a radius of 5 inches is 86.603. 
6 0
3 years ago
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