1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dimaraw [331]
3 years ago
9

Which system in the body is able to fight off most infectious diseases, such as the common cold?

Chemistry
1 answer:
pashok25 [27]3 years ago
7 0
<span>The immune system fights off infectious disease. This is the system which produces cells that fight off the common cold. This system is also very closely related to the lymphatic system. Some people have much stronger immune systems that others.</span>
You might be interested in
A cylindrical rod of length 1 m and radius 1 cm is submerged in water. The rod has a non-uniform mass distribution such that one
Mazyrski [523]

Answer:

A) at the rod's geometrical center

Explanation:

Let us assume that the rod is replaced by water. And now this water volume is in translational and in rotational equilibrium.

Therefore, a net upward force must have been exerted by the surrounding liquid which acts at the center of mass of the water volume.

This force determines through the geometric center of the column of the cylindrical water  

Moreover, the force is also independent of submerged body into it

Hence, the first option is correct

7 0
3 years ago
Taylor, a MIC 206 student needs to determine the OCD of a sample of Escherichia coli. She performed dilutions using four 9 ml di
Troyanec [42]

Answer:

1.37 x 10^6 CFU/mL

Explanation:

First, the dilution factor needs to be calculated.

Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of 10^{-4}.

Next is to divide the colony forming unit from the dilution by the dilution factor:

   137/10^{-4} = 137 x 10^4

In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.

   137 x 10^4/1 = 1.37 x 10^6

Hence, the CFU/ml present in the original <em>E. coli </em> sample is 1.37 x 10^6.

cfu/ml = (no. of colonies x dilution factor) / volume of culture plate

7 0
4 years ago
What is the pH of a solution of KOH with a hydroxide concentration of [OH⁻] = 1.10 x 10⁻⁴
olga2289 [7]

Answer:

p[H+] = 10.042

Explanation:

As we know that

pKw = pH + pOH......eq (1)

we will calculate the pH of OH- and then we will calculate the pH of H+

So p[OH-] = - log [1.10 * 10^{-4}]

Solving the right side of the equation, we get

p[OH-]

= - [-3.958]\\= 3.958

Now we know that

pKw = 14.0

Substituting the value of pOH in the above equation, we get -

14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042

3 0
3 years ago
The density of silver is 10.5 g/cm3. What is the mass (in kilograms) of a cube of silver that measures 0.94 m on each side?
Rzqust [24]

Answer:

8721.132 Kg.

Explanation:

The following data were obtained from the question:

Density (D) of silver = 10.5 g/cm³

Length (L) of silver = 0.94 m

Mass (m) of silver =.?

Next, we shall determine the volume of silver. This can be obtained as follow:

Volume = Length × Length × Length

Volume = L × L × L

Volume = L³

Length (L) of silver = 0.94 m

Volume (V) of silver =?

Volume (V) of silver = 0.94³

Volume (V) of silver = 0.830584 m³

Next, we shall convert 0.830584 m³ to cm³. This can be obtained as follow:

1 m³ = 1×10⁶ cm³

Therefore,

0.830584 m³ = 0.830584 m³ / 1 m³ × 1×10⁶ cm³

0.830584 m³ = 830584 cm³

Therefore, 0.830584 m³ is equivalent 830584 cm³.

Thus, the volume of the silver is 830584 cm³.

Next, we shall determine the mass of the silver. This can be obtained as follow:

Density (D) of silver = 10.5 g/cm³

Volume of the silver = 830584 cm³.

Mass of silver =.?

Density = mass /

10.5 = mass of silver /830584

Cross multiply

Mass of silver = 10.5 × 830584

Mass of silver = 8721132 g

Finally, we shall convert the mass of silver, 8721132 g to kilogram (kg). This can be obtained as follow:

1000 g = 1 Kg

Therefore,

8721132 g = 8721132 g / 1000 g × 1 Kg

8721132 g = 8721.132 Kg

Therefore, the mass of each cube of silver is 8721.132 Kg

3 0
3 years ago
Identify this molecule
Ierofanga [76]
My guess on that molecule is nucleus , sorry if it’s not correct
7 0
3 years ago
Other questions:
  • Hydrocarbons are compounds that are composed of carbon and hydrogen. Which statement does the law of definite proportions suppor
    7·1 answer
  • A solution was prepared by dissolving 31.0 g of kcl in 225 g of water. part a calculate the mass percent of kcl in the solution.
    11·1 answer
  • How do the number of daylight hours affect temperature
    8·2 answers
  • Wat do you pour 1st when diluting an acid? When diluting an acid, always pour 1. the water into the acid. 3. the acid into the w
    10·2 answers
  • Earth's gravitational potential energy: GPE = mgh = Gravity (9.81m/s2) Mass (kg) x Height (m) Kinetic energy: KE = mu? How do th
    5·1 answer
  • How many atoms of Neon in 3.62 moles of Ne?<br> show your work
    5·1 answer
  • Please help!! This would mean so much to me!!
    9·2 answers
  • If Earth is in between the sun and the Moon in both Image 1 and Image 2, why do you think a lunar eclipse is only happening in I
    14·1 answer
  • You mix two amino acids together: glu and ser. If they reacted, how many different dipeptides would you expect to get? List them
    9·1 answer
  • If you rub a magnet over a metal screw driver, you can magnetize the screw driver. This is because the magnet
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!