The vapor of acetic acid will go to the floor of the room.
This is because the density of acetic acid vapor is equal to 2.07 is higher (almost twice) than the density of air which is equal to only 1
Answer:
18.2 g.
Explanation:
You need to first figure out how many moles of nitrogen gas and hydrogen (gas) you have. To do this, use the molar masses of nitrogen gas and hydrogen (gas) on the periodic table. You get the following:
0.535 g. N2 and 1.984 g. H2
Then find out which reactant is the limiting one. In this case, it's N2. The amount of ammonia, then, that would be produced is 2 times the amount of moles of N2. This gives you 1.07 mol, approximately. Then multiply this by the molar mass of ammonia to find your answer of 18.2 g.
I’m not your just blind. I’m sorry
Answer:
a. True
b. False
c. True
d. False
e. False
Explanation:
A. (true) The equilibrium constant K is defined as
In any case
aA +Bb ⇌ Cd +dD
where K is:
![K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%7D)
A large value on K means that the concentration of products is bigger than the concentrations of reagents, so the forward reaction is favored, and the equilibrium lies to the right.
B. (False) When we work with gases, we use partial pressure to make calculations in the equilibrium, so we estimate Kp as:

Using the ideal gas law, we can get a relationship between K and Kp
Pv=nRT where
we know that
is the molar concentration. When we replace P in the expression for Kp we get:
![Kp= \frac{[C]^{c}*(RT)^{c}[D]^{d}*(RT)^{d}}{[A]^{a}*(RT)^{a}[B]^{b}*(RT)^{b}}](https://tex.z-dn.net/?f=Kp%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%2A%28RT%29%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%2A%28RT%29%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%2A%28RT%29%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%2A%28RT%29%5E%7Bb%7D%7D)
Reorganizing the equation:
![Kp= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}*\frac{(RT)^{c+d}}{(RT)^{a+b}}](https://tex.z-dn.net/?f=Kp%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%7D%2A%5Cfrac%7B%28RT%29%5E%7Bc%2Bd%7D%7D%7B%28RT%29%5E%7Ba%2Bb%7D%7D)
We can see K in the expression
Delta n = c+d-a-b
For the reaction

Delta n = 2-1-1=0
So Kp=K in this case.
C. (true) The value of K just depends on the temperature that’s why changing the among of products won’t have any effect on its value.
D. (false) as we can see this reaction involve a heterogeneous system with solids and gases. For convention the concentration for solids and liquids can be considered constant during the reaction that’s why they’re not include in the calculation for the equilibrium constant. Taking this into account the expression for the equilibrium for this reaction is:
So we can see that
is not include in the expression.
E. (False) The equilibrium is defined as the point where the rate of the forward reaction is the same to the rate of the reverse reaction. The value of K is telling you which reaction is favored but the rate of both reactions is the same in this point. (see picture)
O le elo ma muli pipilo ma le kaoga e fai gi o meaoga