<u>Answer:</u> The energy released in the decay process is
<u>Explanation:</u>
The equation for the alpha decay of Ra-226 follows:
To calculate the mass defect, we use the equation:
Mass defect = Sum of mass of product - Sum of mass of reactant
We know that:
Putting values in above equation, we get:
(Conversion factor: 1 kg = 1000 g )
To calculate the energy released, we use Einstein equation, which is:
Hence, the energy released in the decay process is
Answer:
The correct option is the last option.
Explanation:
Generally, when trying to create a mechanical advantage of a lever for an apparatus or a machine, <u>the load is usually moved closer to the fulcrum</u>. Hence, if a lever has a total length of 12 meters and the fulcrum is placed at 6 meters (the center), the best way (based on the previous statement) to double the mechanical advantage of the lever is <u>to move the fulcrum 4 meters toward the side on which the force is applied</u>. The correct option is the last option.
Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
From the question we are told that
The center of gravity of the plane to its nose is
The distance of the front wheel of the plane to its nose is
The distance of the main wheel of the plane to its nose is
At equilibrium the Torque about the nose of the airplane is mathematically represented as
Where m is the mass of the airplane
is the weight of the airplane supported by the main wheel
So
Substituting values
Now the weight supported at the frontal wheel is mathematically evaluated as
Substituting values
Now the weight of the airplane is = mg
Thus percentage of this weight supported by the front wheel is 19.82 %
The answer would be c not that sure tho