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SVETLANKA909090 [29]
3 years ago
8

A plate in a parallel-plate capacitor has an area of 0.03 m2 and is 0.5 × 10–3 m from the other plate. The space between the pla

tes is filled with a dielectric that has a dielectric constant of 6.7. Determine the capacitance of the capacitor. Recall that ε0 = 8.85 × 10–12 Startfraction coulombs squared over Newtons and meters squared Endfraction.
Physics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

4 x 10^-9F

Explanation:

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Which of the following changes will increase the frequency of an oscillating pendulum?
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c. an increase in the length of the rope.

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Write the law of conservation of energy. How does it apply to eating and exercising?
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12. A boy of mass 50 kg running 5m/s jumps on to a 20kg trolley
atroni [7]

Answer:

4 m/s

Explanation:

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m₁ v₁ + m₂ v₂ = (m₁ + m₂) v

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How is sound wave produced?​
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Sound is produced when an object vibrates, creating a pressure wave.

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3 years ago
Read 2 more answers
A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
maksim [4K]

Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

  The first amplitude of the wave is  E_{max}1 =  98.02 \  V/m

  The first  depth  is  D_1 =  10 \  m

   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

   The second depth is D_2 = 100 \ m

Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

=>   \alpha  =  \frac{0.18}{90}

=>    \alpha =  0.002 Np/m

       

4 0
3 years ago
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