On an incline, the force causing the ball to move downwards would be gravity. Additionally, the component of gravity causing this ball to move downwards would be mgsintheta.
Hope this helps!
Answer:
Explanation:
Maximum force of friction possible = μmg
= .65 x 3.8 x 9.8
= 24.2 N
u = 72 x 1000 / 60 x 60
= 20 m /s
v² = u² - 2as
a = 20 x 20 / (2 x 30)
= 6.67 m / s²
force acting on it
= 3.8 x 6.67
= 25.346 N
Friction force possible is less .
So friction will not be able to prevent its slippage
It will slip off .
Answer:
Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Explanation:
Answer: answers B
Explanation: it gets dimmer becuase less light......
Answer:No, the slope won't be too steep
Explanation:
Force is an external agency that causes a body to change its position while friction is a force that causes a body to slide over another. This force is called the frictional force (Ff). The force that causes a body to move is the moving force (Fm).
The slope will be too steep if the frictional force is greater than the moving force since the frictional force tends to oppose the moving force.
According to the explanation, we need to get Ff and compare with the moving force along the plane.
If Ff>Fm it means the slope will be too steep but if Ff<Fm, the slope won't be too steep and as such the body can easily be moved along the plane.
Resolving forces acting along the plane we have FmSintheta + Ff = Fm (FmSintheta and Ff are added because they act in the same direction along the plane)
Fm=50N, theta=5°
Imputing this into the formula to get Ff;
50sin5°+Ff =50
Ff= 50-50sin5°
Ff= 50-4.35
Ff= 45.65N
Since Ff<Fm, this means the slope is not too steep and as such the 30kg load can be moved along the plane easily.
