A plate in a parallel-plate capacitor has an area of 0.03 m2 and is 0.5 × 10–3 m from the other plate. The space between the pla
1 answer:
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Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.
<h3>What is electrical force?</h3>Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
The given data in the problem is
q₁ is the negative charge = 6 µC=6×10⁻⁶ C
q₂ is the positive charge = 3 µC=3×10⁻⁶ C
r is the distance between the charges=0.002 m
is the electric force =?
The value of electric force will be;
Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.
To learn more about the electrical force refer to the link;
Answer:
The potential difference through which an electron accelerates to produce x rays is .
Explanation:
It is given that,
Wavelength of the x -rays,
The energy of the x- rays is given by :
The energy of an electron in terms of potential difference is given by :
So,
V is the potential difference
e is the charge on electron
V = 12431.25 volts
or
So, the potential difference through which an electron accelerates to produce x rays is . hence, this is the required solution.