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VladimirAG [237]

4 years ago

10

If a current of one- or two-tenths of an ampere were to flow into one of your hands and out the other, you would probably be ele

ctrocuted. But if the same current were to flow into your hand and out the elbow above the same hand, you would survive even though the current might be large enough to burn your flesh. Explain.

2 answers:

erastovalidia [21]4 years ago

7 0

If a current of one- or two-tenths of an ampere were to flow into one of your hands and out the other, you would probably be electrocuted. But, if the same current were to flow into your hand and out the elbow above the same hand, you could survive, even though the current might be large enough to burn your flesh

musickatia [10]4 years ago

3 0

Fjtffgh

Explanation:d3d

Fggcyfty

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A sound wave is determined to have a frequency of 1,000 Hz and a wavelength of 35 cm. What is the speed of this wave? If the sou

mars1129 [50]

Answer:

350 m/s

31°C

Explanation:

Speed of sound is given as the product of frequency and wavelength

S=fw

Where s represent the speed in m/s, f is frequency and w is wavelength

Conversion

Taking 1m to be 100 cm then 35 cm will be 35/100=0.35m

Substituting 0.35 m for w and 1000 Hz for f then

S=1000*0.35=350 m/s

speed of sound (m/s) = 331.5 + 0.60 T(°C)

350=331.5+0.6T

T=30.833333333333

The temperature is approximately 31°C

4 0

3 years ago

Jose was out drinking with his friends for nearly the whole night. The next morning he was confused and vomiting, and had a low

Lady bird [3.3K]

Answer:

He has a hangover.

Explanation:

Just something I know.

6 0

2 years ago

At the point of fission, a nucleus of ^235 U that has 92 protons is divided into two smaller spheres, each of which has 46 proto

IrinaK [193]

Answer : $F = 3.5\times10^{3}\ N$

Explanation :

Given that

Radius of sphere $r = 5.90\times 10^{-15}\ m$

The distance between the centers of the two spheres is

$r = 2\times 5.90\times 10^{-15}\ m$

The charge of the sphere $q = 46\times1.6\times10^{-19} C$

The magnitude of the repulsive force between the charges pushing them a part is

Using coulomb law

$F = \dfrac {kq_{1}q_{2}}{r^{2}}$

$F = \dfrac{9\times10^{9}\times (46\times1.6\times10^{-19})^{2}C^{2}}{2\times(5.90\times10^{-15})^{2}\ m^{2}}$

$F = 3501.3\ N$

$F = 3.5\times10^{3}\ N$

Hence, this is the required solution.

3 0

3 years ago

A vehicle of mass 100kg has a kinetic energy of 5000 J at an instant. The velocity at that instant is

snow_lady [41]

Answer:

$\bf\pink{10\:m/s}$

Explanation:

<h2><u>Given</u> :-</h2>

$\sf\red{Mass \ of \ vehicle \ (m) = 100 \ kg}$
$\sf\orange{Kinetic \ energy \ (K.E.) = 5000 \ J}$

<h2><u>To Find</u> :-</h2>

$\sf\green{Velocity\: of\: the \:vehicle \:at \:the \:instant}$

<h2><u>Formula to be used</u> :-</h2>

$\sf\blue{K.E. = \dfrac{1}{2} mv^{2}}$

Where,

K.E. = Kinetic energy possessed by the body
M = Mass of the body
V = Velocity of the body

<h2><u>Solution</u> :-</h2>

$\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}$

$\to\:\:\sf\orange{5000 = \dfrac{1}{2} \times 100 \times v^{2}}$

$\to\:\:\sf\green{5000 = 50 \times v^{2}}$

$\to\:\:\sf\blue{\dfrac{5000}{50} = v^{2}}$

$\to\:\:\sf\purple{100 = v^{2}}$

$\to\:\:\sf\red{\sqrt{100} = v}$

$\to\:\:\sf\orange{ 10 = v}$

$\to\:\:\bf\pink{v = 10\:m/s}$

Velocity of the vehicle at the instant is $\bf\green{10\:m/s}$

7 0

3 years ago

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Just asking how everyone is doing cause of the virus

Bess [88]

Answer:

We are all fiine

Explanation:

How are you doing also

3 0

3 years ago

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