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Montano1993 [528]
3 years ago
14

A hydrogen atom has 1 electron. In which level is it?

Physics
1 answer:
kolezko [41]3 years ago
3 0

If it is in its ground state, it will be in the level 1s

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A moving walkway at an airport has a speed v1 and a length l. a woman stands on the walkway as it moves from one end to the othe
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L = distance traveled.

The woman:
v₁ =  the traveling speed
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The man:
v₁ + v₃ = the traveling speed.
Time of travel = l/(v₁ + v₂)

Answer:
The woman's time is l/v₁.
The man's time is l/(v₁ + v₂).
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Blocks 1 and 2 of masses m1 and m2, respectively are connected by a light string, as show above. These blocks are further connec
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After a wave passes through a medium, particles in the medium
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Answer:

If a particle is affected by a wave, then the particles are displaced. They move along the direction of the wave. Hence, After a wave passes through a medium, particles in the medium are moved along with the wave.

Explanation:

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<span>The Solar System is made up of eight planets, numerous comets, asteroids, and moons, and the Sun. The force that holds all of these objects together is _______.
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How long does it take to raise the temperature of the air in a good-sized living room (3.00m×5.00m×8.00m) by 10.0∘C? Note that t
tekilochka [14]

Answer : The time required is, 16.1 minutes.

Explanation :

First we have to calculate the amount of heat required to increase the temperature is:

Q=mC\Delta T\\\\Q=\rho VC\Delta T

(m=\rho V)

where,

Q = amount of heat required = ?

m = mass

\rho = density of air = 1.20kg/m^3

V = volume of air

C = specific heat of air = 1006J/kg^oC

\Delta T = change in temperature = 10.0^oC

Now put all the given values in above formula, we get:

Q=\rho VC\Delta T

Q=(1.20kg/m^3)\times (3.00m\times 5.00m\times 8.00m)\times (1006J/kg^oC)\times (10.0^oC)

Q=1.449\times 10^6J

Now we have to calculate the time required.

Formula used :

t=\frac{Q}{P}

where,

t = time required = ?

Q = amount of heat required = 1.449\times 10^6J

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Now put all the given values in above formula, we get:

t=\frac{1.449\times 10^6J}{1500W}

t=966s\times \frac{1min}{60s}=16.1min

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5 0
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