Answer:
6000
Step-by-step explanation:
I believe it’s your first choice .
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
I can't see it that good can you text it in please
Step-by-step explanation:
The given line goes up 3 units for every 1 unit it goes to the right, so its slope is 3. If it is made to go through point (2, 1), it will be moved 2 units to the right. This means the y-intercept will be below its current value of 1. The only appropriate choice is ...
... C y = 3x - 5
