Question

in a historical movie, two knights on horseback start from rest at 88.0 m spartans ride directly toward each other to do battle. Sir George’s acceleration has a magnitude of 0.300 m/s^2, while Sir Alfred’s has a magnitude of 0.200 m/s^2. Relative to Sir George’s starting point, where do the knights collide?

Answer 1

The distance formula:d = v i · t + a · t² / 2Sir G.: ( v i = 0 )
d G = 0 + 0.3 · t² / 2Sir A. : d A = 0 + 0.2 t² / 288 m = 0.3 t² / 2   + 0.2 t² / 2    / · 2 ( multiple both sides by 2 )176 = 0.3 t² + 0.2 t²176 = 0.5 t²t² = 176 : 0.5t² = 352t = √352t = 18.76 sd G. = 0.3 · 18.76² / 2 = 0.3 · 352 / 2 = 52.8 mAnswer: The knights collide at 52.8 m relative to Sir George`s starting point.