Answer:
period = 0.65 sec
Explanation:
from the question we are given the following
extension (x) = 2.6 cm = 0.026 m
mass of object (Mo) = 7 g = 0.007 kg
mass of block (Mb) = 28 g = 0.028 g
acceleration due to gravity (g) = 9.8 m/s^{2}
period = 2π x
where k is the spring constant of the spring
and k = \frac{Mo x g}{x}
k = \frac{0.007 x 9.8}{0.026}
k = 2.64 N/m
now period = 2π x
period = 0.65 sec
Answer:
a)Amplitude ,A = 2 mm
b)f=95.49 Hz
c)V= 30 m/s ( + x direction )
d) λ = 0.31 m
e)Umax= 1.2 m/s
Explanation:
Given that
As we know that standard form of wave equation given as
A= Amplitude
ω=Frequency (rad /s)
t=Time
Φ = Phase difference
So from above equation we can say that
Amplitude ,A = 2 mm
Frequency ,ω= 600 rad/s (2πf=ω)
ω= 2πf
f= ω /2π
f= 300/π = 95.49 Hz
K= 20 rad/m
So velocity,V
V= ω /K
V= 600 /20 = 30 m/s ( + x direction )
V = f λ
30 = 95.49 x λ
λ = 0.31 m
We know that speed is the rate of displacement
The maximum velocity
Umax = 1200 mm/s
Umax= 1.2 m/s
Answer:
Explanation:
General Equation of SHM is given by
where x=position of particle
A=maximum Amplitude
angular frequency
t=time
At any time Total Energy is the sum of kinetic Energy and Elastic potential Energy i.e.
where k=spring constant
Potential Energy is given by
also it is given that Potential Energy(U) is equal to Kinetic Energy(K)
Total Energy
Total
at
velocity is