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butalik [34]
3 years ago
15

Baseball player A bunts the ball by hitting it in such a way that it acquires an initial velocity of 1.3 m/s parallel to the gro

und. Upon contact with the bat, the ball is 1.2 m above the ground. Player B wishes to duplicate this bunt, in so far as he also wants to give the ball a velocity parallel to the ground and have his ball travel the same horizontal distance as player A's ball does. However, player B hits the ball when it is 1.6 m above the ground. What is the magnitude of the initial velocity that player B's ball must be given
Physics
2 answers:
zzz [600]3 years ago
7 0

Answer:

d=(1/2)(a)(t^2)+(vi)t

1m=(1/2)(9.8)t^2 vertical initial velocity is 0m/s

t=.45 sec

Then you find the horizontal distance traveled by using

v=d/t

1.3m/s=d/.54sec

d=.585m

Then you need to find the time of player B by using

d=(1/2)(a)(t^2)+(vi)t

1.8m=(1/2)(9.8)(t^2) vertical initial velocity is 0

t=.61 sec

Finally to find player Bs initial horizontal velocity you use the horizontal equation

v=d/t

v=.585m/.61 sec

so v=.959m/s

Explanation:

pashok25 [27]3 years ago
5 0

Answer:

Explanation:

cSep 20, 2010

well, since player b is obviously inadequate at athletics, it shows that player b is a woman, and because of this, she would not be able to hit the ball. The magnitude of the initial velocity would therefore be zero.

Anonymous

Sep 20, 2010

First you need to solve for time by using

d=(1/2)(a)(t^2)+(vi)t

1m=(1/2)(9.8)t^2 vertical initial velocity is 0m/s

t=.45 sec

Then you find the horizontal distance traveled by using

v=d/t

1.3m/s=d/.54sec

d=.585m

Then you need to find the time of player B by using

d=(1/2)(a)(t^2)+(vi)t

1.8m=(1/2)(9.8)(t^2) vertical initial velocity is 0

t=.61 sec

Finally to find player Bs initial horizontal velocity you use the horizontal equation

v=d/t

v=.585m/.61 sec

so v=.959m/s

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Natali5045456 [20]

when wire is coiled upon a nail then it will posses magnetic characteristics

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B = \mu_o ni

so here when wire is coiled up on a nail then due to the magnetic field of the coil the nail will attain magnetic characteristic.

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<em>Possess magnetic properties </em>

5 0
3 years ago
Read 2 more answers
At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder
bearhunter [10]

Answer:

<em>The lighten travels 0.853 miles.</em>

Explanation:

Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.

v = 2x/t .......................................... Equation 1

making x the subject of the equation

x = vt/2........................................ Equation 2

Where v = velocity of sound in air, x = distance traveled by the sound, t = time

Given: v = 344 m/s t = 8 s

Substituting into equation 2

x = 344(8)/2

x = 1376 m.

x = 1376×0.00062 miles = 0.853 miles

<em>Thus the lighten travels 0.853 miles.</em>

4 0
3 years ago
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The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to
kakasveta [241]

Answer:

The angle from the vertical is 48.72°

Explanation:

Given :

Length of rope l = 3.10 m

Mass of man m = 76 Kg

Mass of car M = 1520 Kg

Velocity of car v = 1.01 \frac{m}{s}

According to conservation law,

Potential energy of man is converted to kinetic energy of car moving,

   \frac{1}{2} M v^{2} = mgh

We calculate height,

   h = \frac{M v^{2} }{2mg}

   h = \frac{1520(1.01)^{2} }{2\times 75 \times 9.8}                      ( ∵ g = 9.8 \frac{m}{s^{2} } )

   h = 1.05 m

This is the distance of the rope at the bottom,

So we take difference of it.

⇒ 3.10 - 1.05 = 2.05

We can calculate angle between them,

\cos \theta = \frac{2.05}{3.10}  = 0.6597

 \theta = 48.72°

Therefore, the angle from the vertical is 48.72°

8 0
3 years ago
Describe two characteristics that can be determined about a star by analyzing the spectra of the star.
VARVARA [1.3K]

Answer:

Effective temperature, Doppler velocity

Explanation:

Since star behave localy as a blackbody, Wíen's displacement law can be use in order to determine its effective temperature. From the spectrum it will be take the wavelength at which is the peak of emission greater in the continuum

 

Then, the maximum peak of emission (\lambda_{max}) will be replace in the next equation of the Wien's displacement law:

T = \frac{2.898x10^{-3} m. K}{\lambda max} (1)

Where T is the effective temperature of the star.

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

By using that shift in the spectral lines it can be determine the Doppler velocity.

v = c\frac{\Delta \lambda}{\lambda_{0}}  (2)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the wavelength at rest, v is the velocity of the source and c is the speed of light.

8 0
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kotegsom [21]
What you want.. you would need to post your question
8 0
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