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Basile [38]
3 years ago
9

the structure shown in the picture is made of copper. The three thin rods are of equal dimensions. The single main rod is heated

to 400 °C and then is brought into contact with the rods P, Q, and R. After several minutes, the temperatures of rods P, Q, and R are recorded. Which option gives the correct values of the final temperatures of rods P, Q, and R? A) P = R < Q B) P = Q = R C) P = R > Q D) P = Q < R
Physics
2 answers:
charle [14.2K]3 years ago
4 0

If you are on USA Test prep the answer is B

julia-pushkina [17]3 years ago
3 0

The answer is B) P = Q = R

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How do you feel about the way land is used around you?
cupoosta [38]

Answer:

I feel that people hurt the land and are destroying. I think they aren't using the land for the right reasons.

5 0
2 years ago
What volume will be occupied by 20g of Copper if the density of Copper is 9.1g/ml?
Eva8 [605]

Answer:

The volume of copper is 2.198 ml

Explanation:

Given;

mass of copper, m = 20 g

density of copper, ρ = 9.1 g/ml

Density is given by;

Density = mass / volume

Volume = mass / density

Volume = (20 g) / (9.1 g/ml)

Volume = 2.198 ml

Therefore, the volume of copper is 2.198 ml

3 0
3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 500 rev/s. If such a star has a radius of 17
Alexus [3.1K]

Answer:

7.22 × 10²⁹ kg

Explanation:

For the material to be in place, the gravitational force on the material must equal the centripetal force on the material.

So, F = gravitational force = GMm/R² where M = mass of neutron star, m = mass of object and R = radius of neutron star = 17 km

The centripetal force F' = mRω² where R = radius of neutron star and ω  = angular speed of neutron star

So, since F = F'

GMm/R² = mRω²

GM = R³ω²

M = R³ω²/G

Since ω = 500 rev/s = 500 × 2π rad/s = 1000π rad/s = 3141.6 rad/s = 3.142 × 10³ rad/s and r = 17 km = 17 × 10³ m and G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

Substituting the values of the variables into M, we have

M = R³ω²/G

M = (17 × 10³ m)³(3.142 × 10³ rad/s)²/6.67 × 10⁻¹¹ Nm²/kg²

M = 4913 × 10⁹ m³ × 9.872 × 10⁶ rad²/s²/6.67 × 10⁻¹¹ Nm²/kg²

M = 48,501.942 × 10¹⁵ m³rad²/s² ÷ 6.67 × 10⁻¹¹ Nm²/kg²

M = 7217.66 × 10²⁶ kg

M = 7.21766 × 10²⁹ kg

M ≅ 7.22 × 10²⁹ kg

8 0
2 years ago
The driver sees that the road is empty and accelerates at 1.0 m/s2 for 5.0 s. what can you determine about the truck's motion us
vekshin1

kinematic equation

v=u+at

v-u=at

v-u = 1x5

the driver will have increased speed by 5 m/s. actual speeds unknown

7 0
3 years ago
DUE IN 15 MIN!
Fiesta28 [93]

Answer:

Law of multiple proportions

8 0
2 years ago
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