The "blue" object would look the same. Say that this blue object is a square. That "square" is every color but blue. The only reason that you see it as "blue" is because what we call "blue", it the only color of light that bounces back at our eyes. Under all colors of light, especially simultaneously. This square or any shape for that matter would absorb the other colors of light, but the blue will be rejected. Therefore, we can only see what bounces back at our eyes, which is the color blue in this case.
Hope this helps, WyattMarine501
Answer:
circular motion
In surface waves, particles of the medium undergo a circular motion. They are neither longitudinal nor transverse, for in longitudinal and transverse waves, all the particles in the entire bulk of the medium move in a parallel and a perpendicular direction, respectively, relative to the direction of energy transport.
Explanation:
Hope this helps
1. Mass number = Protons + Neutrons
Mass number = 26 + 32 = 58
2. Let the element be Xy
58Xy26
3. The proton number of Strontium is 38.
Mass = 38 + 50 = 88
4. 88Sr38
5. Let the atom be Ab
72Ab32
In that case, there are three possible scenarios:
-- If the braking force is less than the force delivered by the engine,
then the car will continue to accelerate, and the brakes will eventually
overheat and erupt in flame.
-- If the braking force is exactly equal to the force delivered by the engine,
then the car will continue moving at a constant speed, and the brakes will
eventually overheat and erupt in flame.
-- If the braking force is greater than the force delivered by the engine,
then the car will slow down and eventually stop. If it stops soon enough,
then the absorption of kinetic energy by the brakes will end before the
brakes overheat and erupt in flame. Even if the engine is still delivering
force, the brakes can be kept locked in order to keep the car stopped ...
They do not absorb and dissipate any energy when the car is motionless.
Answer:
Explanation:
We shall solve this problem on the basis of averaging , otherwise it will require integration which is a complex operation .
According to newton's law of cooling
dQ / dt = k ( T₁ - T₂ )
T₁ is temperature of surrounding and T₂ is temperature of object .
For the heating by 2 degree
dQ = ms x ΔT , m is mass , s is specific heat and ΔT is rise of
= ms x 2
dt = 1 second
T₁ the average temperature of object = (30 + 32) / 2 = 31
dQ = ms x ΔT
ms x 2 = k ( 100 - 31 )
k = 2 ms / 69
In the second case bar's temperature rises from 32 to 70
average temperature = 32 + 70 / 2 = 51
If t be the time required
dQ = ms x ( 70 - 32 ) = 38ms
38ms / t = k ( 100 - 51 )
38ms / t = (2ms / 69) x 49
t = 38 x 69 / (2 x 49)
= 26.75 s .
