Answer:
<h2>
3,654 different ways.</h2>
Step-by-step explanation:
If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).
Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.
29C3 = 29!/(29-3)!3!
29C3 = 29!/(26!)!3!
29C3 = 29*28*27*26!/26!3*2
29C3 = 29*28*27/6
29C3 = 3,654 different ways.
This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders
The answer would be the first one, (measure 1 is equal to 1/2(SP + QR)). You would just use the formula for intercepted arcs.
The common difference, d, can be determined by subtracting the two consecutive values:
1 - 5 = -4
-3 - 1 = -4
-7 - -3 = -4
Then, using the equation:
an = a1+ d(n-1)
a_21 = 5 + (-4)(21 - 1)
a_21 = -75
The answer is letter D. I hope I was able to help you. Have a good day!
Answer:
<h2>$6049.63</h2>
Step-by-step explanation:
the objective is to maximize profit
let x be corn and y be oat
let us begging by formulating the linear program for the problem
The objective function is
111x+47y=P
The constraints are
1. capital
36x+18y=2100------------1
2. labor
6x(8)+2y(8)=2400
48x+16y=2400-------------2
solving 1 and 2 we apply substitution method
36x+18y=2100------1
36x=2100-18y
x=(2100-18y)/36
put x=(2100-18y)/36 in 2 we have
48(2100-18y)/36+16y=2400
(100800-864y)/36+16y=2400
2800-24y+16y=2400
-8y=2400-2800
-8y=-400
8y=400
y=400/8
y=50
to find x put y=50 in 36x+18y=2100------------1
36x+18(50)=2100------------1
36x+900=2100
36x=2100-900
36x=1200
x=1200/36
x=33.33
profit is
111x+47y=P
111(33.33)+47(50)=P
3699.63+2350=P
P=6049.63
$6049.63
the planning comnination is to work on
33.33 acre of corn and 50 acre of oat
Answer:
a) 21%
b) 45.5%
c) 26.4%
Step-by-step explanation:
Given the supplied information, a table of probabilities can be constructed. (See the attachment.) The numbers across the bottom reflect the given ratios of customers selecting the different gas types. The numbers in the cells are those bottom numbers multiplied by the percentage that fill the tank (or not). The numbers on the right are the sums of the numbers in each row.
a) The top center cell in the table answers this question. It it the product ...
p(plus)×p(fill | plus) = 0.35×0.60 = 0.21 = 21%
__
b) The sum on the right answers this question:
p(fill) = 45.5%
__
c) The ratio of the first column number (12%) to the row sum for Fill (45.5%) answers this question:
p(regular | fill) = 12%/45.5% ≈ 26.4%
