we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form
or 
where
k is the constant of variation
in this problem we have
the point 
so

substitute


therefore
<u>the answer is</u>

Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
Answer:
there are 3 red fish
Step-by-step explanation:
1:5
_:15
5 times 3 =15
so 1 times 3 =3
Answer:



Step-by-step explanation:
Let
x----> the length of the rectangular garden
y---> the width of the rectangular garden
we know that
The perimeter of the rectangle is equal to

we have

so

simplify

------> equation A
Remember that the area of rectangle is equal to
----> equation B
substitute equation A in equation B
----> this is a vertical parabola open downward
The vertex is a maximum
The y-coordinate of the vertex is the maximum area
The x-coordinate of the vertex is the length side of the rectangle that maximize the area
using a graphing tool
The vertex is the point 
see the attached figure
so

Find the value of y

The garden is a square
the area is equal to
----> is equal to the y-coordinate of the vertex is correct