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tresset_1 [31]
3 years ago
10

What is the equation of the line in slope-intercept form?

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0
The answer is b. Because x is always 1. So your going up 1 over one each time so it’s positive x. And your starting at negative 8 which is down 8. Therefore your answer is b.
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Anfernee bought 4 umbrellas and 2 hats and spent between $40 and $60. Each umbrella costs the same amount. Each hat costs the sa
Alisiya [41]
8+8=16
40-16=24
24/4=6
the least amount that could have been spent on an umbrella is $6
60-16=44
44/4=11
the most amount that could have been spent on an umbrella is $11 


7 0
4 years ago
The annual rainfall (in inches) in a certain region is normally distributed with mean 43.2 and variance 20.8. Assume rainfall in
Wittaler [7]

Answer:

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

\mu = 43.2, \sigma = \sqrt{20.8} = 4.56

Probability that a year has rainfall of more than 50 inches.

pvalue of Z when X = 50. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 43.2}{4.56}

Z = 1.49

Z = 1.49 has a pvalue of 0.9319

1 - 0.9319 = 0.0681

Find the probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

This is P(X \leq 2) when n = 15, p = 0.0681. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.0681)^{0}.(0.9319)^{15} = 0.3472

P(X = 1) = C_{15,1}.(0.0681)^{1}.(0.9319)^{14} = 0.3805

P(X = 2) = C_{15,2}.(0.0681)^{2}.(0.9319)^{13} = 0.1947

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.3472 + 0.3805 + 0.1947 = 0.9224

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

8 0
3 years ago
Read 2 more answers
Ted is not particularly creative. He uses the pickup line​ "If I could rearrange the​ alphabet, I'd put U and I​ together." The
sp2606 [1]

Answer:

No, the sum of all the probabilities is not equal to 1.

Step-by-step explanation:

Given

\begin{array}{ccccc}x & {0} & {1} & {2} & {3} & {P(x)} & {0.001} & {0.007} & {0.033} & {0.059}  \ \end{array}

Required

Determine if the given parameter is a probability distribution

For a probability distribution to exist, the following must be true;

\sum P(x)=1

So, we have:

\sum P(x) = 0.001 + 0.007 + 0.033 + 0.059

\sum P(x) = 0.1

<em>Hence, it is not a probability distribution because the sum of all probabilities is not 1</em>

4 0
3 years ago
The height of a door is 210 cm.
lana66690 [7]
210 / 6 = 35

---------------

This means that 1/6 of 210 is 35.

----------------

What is 5/6 of 210 though??

If 1/6 of 210 is 35, 5/6 of 210 is...

5 x 35 = 175

-----------

Answer: 175 cm
4 0
3 years ago
Suppose f(x, y) is a differentiable function of x and y and let g(r, s) = f (2rs, 8s − 2r). Use
worty [1.4K]

By the chain rule,

\dfrac{\partial g}{\partial r} = \dfrac{\partial f}{\partial r} \\\\ ~~~~~ = \dfrac{\partial f}{\partial x} \dfrac{\partial x}{\partial r} + \dfrac{\partial f}{\partial y} \dfrac{\partial y}{\partial r} \\\\ ~~~~~ = 2 s \dfrac{\partial f}{\partial x} - 2 \dfrac{\partial f}{\partial y}

where x(r,s)=2rs and y(r,s)=8s-2r.

If r=2 and s=1, then

x = 2\cdot2\cdot1 = 4

y=8\cdot1-2\cdot2 = 4

so that

g_r(2,1) = 2\cdot1 f_x(4,4) - 2 f_y(4,4) = 2\cdot2-2\cdot3 = \boxed{-2}

5 0
1 year ago
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