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Kamila [148]
3 years ago
15

Help me please can someone explain

Mathematics
1 answer:
serg [7]3 years ago
8 0

Answer:

Step-by-step explanation:

7x+4^3+5  just answer that ans that will givin u your answer

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tickets for a school carnival cost $10 for adults and $5 for children . last saturdays carnival sold 170 tickets worth a total o
Alex
So (a) stands for adult and (c) is for child.

10a+5c=1200(total cost) 

a+c=170(for tickets sold)

There are 70 adult tickets and 100 child tickets.

6 0
3 years ago
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A new bank customer with ​$2,500 wants to open a money market account. The bank is offering a simple interest rate of 1.9​%.
Alika [10]

Answer:

He will earn $69000

Step-by-step explanation:

Think about it. The illuminati is real and 420 is a number. Its quite easy math. Now please go and **** yourself

8 0
3 years ago
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Differentiating Functions of Other Bases In Exercise, find the derivative of the function.
aniked [119]

Answer:

\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}

Step-by-step explanation:

We are given the following in the question:

y = \ln {16}(x^2 - 3x)

We have to find the derivative of the given expression.

y = \ln 16(x^2 - 3x)\\\text{Using the log propert}\\\\\log_a b = \dfrac{\log b}{\log a}\\\\dfrac{d(x^n)}{dx} = nx^{n-1}\\\\\dfrac{d(\log x)}{dx} = \dfrac{1}{x}\\\\\text{\bold{Differentiating we get}}\\\\\displaystyle\frac{dy}{dx} = \frac{d(\ln 16(x^2-3x))}{dx}\\\\= \frac{1}{16(x^2-3x)})\frac{d(x^2-3x)}{dx}\\\\=\frac{1}{\log 16(x^2-3x)}(2x - 3)\\\\= \frac{2x-3}{\ln 16(x^2 - 3x)}

\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}

7 0
4 years ago
A boat takes 55 hours to go 20 miles upstream. It can go 50 miles downstream in the same time. Find the rate of the current and
sergey [27]

We have two unknowns and two equations so we can solve this question.

The two unknowns are C (speed of current) and B (speed of boat)

Our boat traveled 20 miles in 55 hours going upstream which means it traveled .36 miles in 1 hour; in other words .36mph . Our boat traveled 50 miles in 55 hours going downstream; in other words .909mph .

We can assume that because the boat managed to cover distance in the direction it was headed upstream it must have been going faster than the current so it moved at the speed of the boat minus the speed of the current and when it was going downstream it moved at the speed of the boat plus the speed of the current.

This gives us;

.36mph = B - C

.909mph= B + C

We solve for this system of equations and it simplifies to 1.27mph=2B

and B= .636mph

Plug this into one of the equations and we get that C= .2727mph

This means that the boat moved at .363mph and the current moved at .2727mph.

6 0
3 years ago
HELP!! I WILL GIVE BRAINLIEST
FrozenT [24]

Number one: Just plot down on the number like the numbers you have. Just took the test for this.

3 0
3 years ago
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