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grandymaker [24]
3 years ago
8

What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?

Chemistry
1 answer:
Westkost [7]3 years ago
6 0
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



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The empirical formula is C₇H₆O₂.

Assume that you have 100 g of the compound.

Then you have 68.84 g C and 4.962 g H.

Mass of O = (100 – 68.84 – 4.962) g = 26.20 g O.

Now, we must convert these masses to moles and find their ratios.

From here on, I like to summarize the calculations in a table.

<u>Element</u>     <u>Mass/g</u>    <u>Moles</u>    <u>Ratio</u>    <u> ×2</u>   <u>Integers</u>  

     C           68.84      5.732    3.501  7.001       7

     H            4.962    4.923    3.006  6.012      6

     O          26.20      1.638     1          2             2

The empirical formula is C₇H₆O₂.

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