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grandymaker [24]
4 years ago
8

What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?

Chemistry
1 answer:
Westkost [7]4 years ago
6 0
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



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Answer:

The aqueous solution of Na_{3} Po_{4} therefore would be "strongly basic."

Explanation:

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Korvikt [17]

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