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grandymaker [24]
3 years ago
8

What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?

Chemistry
1 answer:
Westkost [7]3 years ago
6 0
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



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Answer:

9.91 mL

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (torr)

P2 = final pressure (torr)

V1 = initial volume (mL)

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According to the information provided in this question;

V1 = 15.0mL

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Using P1V1/T1 = P2V2/T2

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