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TiliK225 [7]
3 years ago
12

Helppppppppppppppppppppp

Mathematics
1 answer:
Greeley [361]3 years ago
6 0

Answer: 144ft

Step-by-step explanation: Hope this help :D

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Integral Calculation
Tatiana [17]

Answer:

\frac{4}{3(e^2+1)}

Step-by-step explanation:

We want to evaluate:

\int\limits^1_{-1} {\frac{x^2+1}{e^2+1} } \, dx

This is the same as:

\frac{2}{e^2+1} \int\limits^1_{0} {x^2+1} \, dx

We integrate to obtain:

\frac{2}{e^2+1} (\frac{x^3}{3}+x)|_0^1

We evaluate to obtain:

\frac{2}{e^2+1} (\frac{1^3}{3}+1)=\frac{4}{3(e^2+1)}

8 0
3 years ago
Write each of the following expressions as a powers of 2: (4·25)÷(23· 1/16 )
WITCHER [35]
<span>(4 · 2^5) ÷ (2^3 · 1/16 )

</span>= (2^2 · 2^5) ÷ (2^3 · 2^-4 )

= (2^7) ÷ (2^-1)

= 2^8
6 0
2 years ago
The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
likoan [24]

Answer:

A)  3%

B)  Product A

Step-by-step explanation:

<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

<u>Part A</u>

<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

  • a = 10,100
  • b = 1.01
  • n = t - 1 (as the initial value is for t = 1 not t = 0)

\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

4 0
2 years ago
Pls HELP WITH THESE TWO QUESTIONS NO LINKS
Marta_Voda [28]

Answer:

The answer to the first question is B.

The answer to the second question is C.

7 0
2 years ago
Read 2 more answers
Can anyone help me with this question? &lt;3 please and thank you!
vazorg [7]

Answer: 3/2 I’m on something similar rn

Step-by-step explanation:

6 0
2 years ago
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