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3 years ago

It takes 50 seconds for Tyler to do 450 Joules of work. How much power did Tyler use?

Physics

2 answers:

Bogdan [553]3 years ago

8 0

Power=work/time
So,
Power =450/50=9watts

My name is Ann [436]3 years ago

7 0

Answer:

Power = 450 Joules / 50 seconds = 9 J/s = 9 W *average* power

Explanation:

Power = Energy / Time ( or Work / Time) just as Velocity = Distance / Time

So, the average power needed for 50 seconds to do 450 Joules of work is simply 450 J / 50 s = 9 J/s = 9 Watts (The unit Watt is defined so that 1 Watt = 1 Joule / Second). It's important to note that 9W is the *average* power. The problem does not say that Tyler does work at a constant rate, so it's worth adding that caveat to the answer!

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vivado [14]

Given  :

Object position ( u ) = - 36 cm
focal length ( f ) = - 16 cm
image position ( v ) = ?

now, we know

=》

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

=》

$\frac{1}{ - 16} = \frac{1}{ - 36} + \frac{1}{v}$

=》

$\frac{1}{v} = \frac{ - 1}{16} - \frac{ - 1}{36}$

=》

$\frac{1}{v} = \frac{ - 9 - ( - 4)}{144}$

=》

$\frac{1}{v} = \frac{ - 9 + 4}{144}$

=》

$\frac{1}{v} = \frac{ -5}{144}$

=》

$v = \frac{144}{ - 5}$

=》

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So, image position = 28.8 cm, at same side of object .

8 0

3 years ago

If the tensile strength of the Kevlar 49 fibers is 0.550 x 106 psi and that of epoxy resin is 11.0 x103 psi, calculate the stren

Elina [12.6K]

Answer:

$\sigma_{tot} =436810 psi$

Explanation:

Notation

$\sigma_{fib} =0.55x10^6 psi$ represent the tensile strength for the Kevlar 49 fibers

$\sigma_{epox} =11x10^3 psi$ represent the tensile strength for the epoxy resin

79% by volume is made of Kevlar 49 fibers

The rest 100-79=21% is made of epoxy resin

Tensile strength is a "measurement of the force required to pull something such as rope, wire, or a structural beam to the point where it breaks". Can be defined as "the maximum amount of tensile stress that it can take before failure".

For this case we need to use a basis of calculus since we don't know the total volume but we can assume a reference value on order to make the calculations.

If we assume a total volume of $V_{tot}=1 in^3$ we can do the follwoing balance:

$\sigma_{tot}V_{tot}=\sigma_{fib}V_{fib} +\sigma_{epox}V_{epox}$

We can replace the values given:

$\sigma_{tot}=(0.55x10^6 psi)(0.79) +(11x10^3 psi)(1-0.79)$

$\sigma_{tot} =436810 psi$

So then the strength of the composite material is : $\sigma_{tot} =436810 psi$

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4 years ago

What are the steps that produce electricity from this fuel

deff fn [24]

The nuclear fuel cycle is the series of industrial processes which involve the production of electricity from uranium in nuclear power reactors.
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3 years ago

How do we get this equation ?? H=V^2÷R

lesantik [10]

$H=\frac{V^2}{R}\times t$ is the equation that represents the Joule's law of heating.

<h3>Explanation:</h3>

Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to

1. Square of Current (I²),

2. Resistance of the conductor (R)

3. Time for which current is passed (t)

Hence, Heat generated = $H = I^2 Rt$ .....................(1)

By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).

$V\ \alpha\ I\\V=I\times R$ ...............................................(2)

From (2), Current (I) can be rewritten as

$I = \frac{V}{R}$ ........................................................(3)

Substituting (3) in (1), we get

$H = I^2\times R\times t \\=(\frac{V}{R} )^2\times R\times t\\\\=\frac{V^2}{R^2}\times R\times t = \frac{V^2}{R}\times t\\\\ H =\frac{V^2}{R}\times t$

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3 years ago

What is the accletation of a 1500kg with a net force of 7500 N

matrenka [14]

Acceleration formulae is:
a=Fnet/mass
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3 years ago

It takes 50 seconds for Tyler to do 450 Joules of work. How much power did Tyler use?​

It takes 50 seconds for Tyler to do 450 Joules of work. How much power did Tyler use?