The solution to the questions are given as


- the direction of induced current will be Counterclock vise.
<h3>What is the direction of the
current induced in the loop, as viewed from above the loop.?</h3>
Given, $B(t)=(1.4 T) e^{-0.057 t}$




(b) 

c)
In conclusion, the direction of the induced current will be Counterclockwise.
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From Newton's second law, we know F = ma, where a is the acceleration and m is the mass in kg.
F = 1000kg * 9.8m/s = 9800N
F = 9800 N
Hope this helps!
1) 9.57 N
We have two forces applied on the apple:
- The force of gravity, in the downward direction:
W = 9.42 N
- The force exerted by the wind, in the horizontal direction (to the right):
Fw = 1.68 N
The two forces are perpendicular to each other, so we can find the magnitude of the net force by using Pythagorean's theorem.
Therefore, we have:

2) 
The direction of the net external force, measured from the downward vertical, can be measured using the following formula:

where
is the force in the horizontal direction
is the force in the vertical direction
In this problem,


and so we find:

Answer:
this question does not make sense could you please make it clearer