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3 years ago

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I NEED THIS ANSWER ASAP PLEASE!!! What happens when a light ray passes through the focal point, and then reflects off of a conve

x mirror? A.The reflected ray will run parallel to the center of curvature. B. The reflected ray will run parallel to the principal axls. C. The reflected ray will pass through the center of curvature. D. The reflected ray will pass through a point between the center of curvature and the focal point. E. The reflected ray will pass through a point between the focal point and the vertex

1 answer:

Alexandra [31]3 years ago

8 0

What happens when a light ray passes through the focal point, and then reflects off of a convex mirror?

E. The reflected ray will pass through a point between the focal point and the vertex

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Strontium has how many neutrons

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Answer:

50

Explanation:

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A man of weight Wman is standing on the second floor and is pulling on a rope to lift a box of weight Wbox from the floor below.

slavikrds [6]

Answer:

Explanation:

See the attached figure . See the forces acting on man pulling up the box .

Man is stationary so net force acting on man is zero .

T + R = Wman

R is the reaction force of the ground of second floor .

R = Wman - T

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3 years ago

Find the direction and magnitude of the net force exerted on the point charge q3 in the figure. Let q= +2.4 μC and d= 33cm.

kobusy [5.1K]

With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x $10^{11}$ N and 66 degrees

ELECTRIC FORCE (F)

F = $\frac{KQq}{d^{2} }$

Where K = 9 x $10^{9}$ N $m^{2}$ / $C^{2}$

The distance between $q_{1}$ and $q_{3}$ can be calculated by using Pythagoras theorem.

d = $\sqrt{33^{2} + 33^{2} }$

d = 46.7 cm = 0.467 m

For force $F_{1}$ , substitute all the parameters into the formula above

$F_{1}$ = (9 x $10^{9}$ x 3 x 1)/ $0.467^{2}$

$F_{1}$ = 2.7 x $10^{10}$ /0.218

$F_{1}$ = 1.24 x $10^{11}$ N

For force $F_{4}$ , substitute all the parameters into the formula above

$F_{4}$ = (9 x $10^{9}$ x 3 x 4)/ $0.33^{2}$

$F_{4}$ = 1.08 x $10^{11}$ /0.1089

$F_{4}$ = 9.92 x $10^{11}$ N

For force $F_{2}$ , substitute all the parameters into the formula above

$F_{2}$ = (9 x $10^{9}$ x 3 x 2)/ $0.33^{2}$

$F_{2}$ = 5.4 x $10^{10}$ /0.1089

$F_{2}$ = 4.96 x $10^{11}$ N

Summation of forces on Y component will be

$F_{y}$ = $F_{4}$ - $F_{1}$ Sin 45

$F_{y}$ = 9.92 x $10^{11}$ - 1.24 x $10^{11}$ Sin 45

$F_{y}$ = 9.04 x $10^{11}$ N

Summation of forces on X component will be

$F_{x}$ = $F_{2}$ - $F_{1}$ Cos 45

$F_{x}$ = 4.96 x $10^{11}$ - 1.24 x $10^{11}$ Sin 45

$F_{x}$ = 4.08 x $10^{11}$ N

Net Force = $\sqrt{F_{x} ^{2} + F_{y} ^{2} } }$

Net force = $\sqrt{(4.08*10^{11}) ^{2} + (9.04*10^{11}) ^{2} }$

Net force = 9.9 x $10^{11}$ N

The direction will be

Tan ∅ = $F_{y}$ / $F_{x}$

Tan ∅ = 9.04 x $10^{11}$ / 4.08 x $10^{11}$

Tan ∅ = 2.216

∅ = $Tan^{-1}$ (2.216)

∅ = 65.7 degrees

Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x $10^{11}$ N and 66 degrees approximately.

Learn more about electric Force here: brainly.com/question/4053816

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2 years ago

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If an earthquake occurred in Miami, Florida, then how long would it take for a seismic station in Seattle, Washington, to pick u

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0.017s

Explanation:

Given parameter

Distance = 5000km = 5 x 10⁶m

Unknown:

time taken = ?

Solution:

We use the normal speed equation to solve this problem as we take the speed of the wave to be 3 x 10⁸m/s.

Speed = $\frac{Distance }{Time taken}$

Inputting the parameters:

Time taken = $\frac{distance }{velocity of the wave}$

Time taken = $\frac{ 5 000000}{3 00000000}$ = 0.017s

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2 years ago

What Is a Sound Wave? Learning Goal: To understand the nature of a sound wave, including its properties: frequency wavelength, l

NISA [10]

Answer:

A) Propagation of pressure fluctuations in a medium

B) air is the medium in which the wave is transported,

Explanation:

Part A.

A sound wave is a longitudinal oscillation of the molecules that forms in a material medium, they can be solid, liquid or gases, therefore the wave propagates in the same direction as the oscillation of the particles.

The most correct answer is:

* Propagation of pressure fluctuations in a medium

Part b

air is the medium in which the wave is transported, otherwise it cannot propagate

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3 years ago