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Thepotemich [5.8K]
3 years ago
14

You place an object 36.0 cm in front of a concave

Physics
1 answer:
vivado [14]3 years ago
8 0

<em><u>Given</u></em><em> </em> :

  • <em>O</em><em>bject </em><em>position</em><em> </em>( u ) = - 36 cm
  • <em>focal</em><em> </em><em>length</em><em> </em>( f ) = - 16 cm
  • <em>image position</em><em> </em>( v ) = ?

now, we know

=》

\frac{1}{f}  =  \frac{1}{v}  +  \frac{1}{u}

=》

\frac{1}{ - 16}  =  \frac{1}{ - 36}  +  \frac{1}{v}

=》

\frac{1}{v}  =  \frac{ - 1}{16}  -  \frac{ - 1}{36}

=》

\frac{1}{v}  =  \frac{ - 9 - ( - 4)}{144}

=》

\frac{1}{v}  =  \frac{ - 9 + 4}{144}

=》

\frac{1}{v}  =  \frac{ -5}{144}

=》

v =  \frac{144}{ - 5}

=》

<em><u>v =  - 28.8</u></em>

So<em><u>, image position</u></em> = 28.8 cm, at same side of object .

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