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harina [27]
3 years ago
5

Initial velocity=3m/s, final velocity=5m/s, displacement=2m. Find the acceleration.

Physics
2 answers:
shusha [124]3 years ago
4 0

Answer:

Explanation:

To analyze the behavior of black bears during the night. To describe how black bears adapt to life near human. To evaluate the decline in the number of black bear.

MrRa [10]3 years ago
4 0

<u>Acceleration = 4 m/s² </u>

Step-by-step explanation:-

Let's solve this question easily...

Given,

Initial velocity (u) = 3 m/s

Final velocity (v) = 5 m/s

Displacement (s) = 2m

Using the formula,

\frac{ {v}^{2} -  {u}^{2}  }{2as}

So, in order to get the value of a, let's do:

a =  \frac{ {v}^{2} -  {u}^{2}  }{2s}

Now substitute all the given values. So,

a =  \frac{ {5}^{2} -  {3}^{2}  }{2 \ \times 2}

a =  \frac{25 - 9}{4}

a =  \frac{16}{4}

a = 4 \: m / {s}^{2}

Note:- You can also write the answer as:

4 \: m. {s}^{ - 2}

Therefore, the answer is <u>4</u><u> </u><u>m</u><u>/</u><u>s²</u> or <u>4 m.s^-2</u>

✍️ <em>By </em><em>Benjemin</em> ☺️

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8 0
3 years ago
An object is thrown straight up with an initial velocity of 10 m/s, and there is an air resistance force causing an acceleration
lana [24]

Answer:

Vf= 7.29 m/s

Explanation:

Two force act on the object:

1) Gravity

2) Air resistance

Upward motion:

Initial velocity = Vi= 10 m/s

Final velocity = Vf= 0 m/s

Gravity acting downward =  g = -9.8 m/s²

Air resistance acting downward = a₁ = - 3 m/s²

Net acceleration = a = -(g + a₁ ) = - ( 9.8 + 3 ) = - 12.8 m/s²

( Acceleration is consider negative if it is in opposite direction of velocity )

Now

2as = Vf² - Vi²

⇒ 2 * (-12.8) *s = 0 - 10²

⇒-25.6 *s = -100

⇒ s = 100/ 25.6

⇒ s = 3.9 m

Downward motion:

Vi= 0 m/s

s = 3.9 m

Gravity acting downward =  g = 9.8 m/s²

Air resistance acting upward = a₁ = - 3 m/s²

Net acceleration = a = g - a₁  =  9.8 - 3  = 6.8 m/s²

Now

2as = Vf² - Vi²

⇒ 2 * 6.8 * 3.9 = Vf² - 0

⇒ Vf² = 53. 125

⇒ Vf= 7.29 m/s

8 0
3 years ago
If one object is 103 km away and a second object is 106 km away, one could say that the second object is _____ times further awa
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Answer:

1.03

Explanation:

\frac{object_{second}}{object_{first}} = \frac{106}{103} = 1.02912621359

Round to three significant digits

1.03

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6 0
2 years ago
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Average speed is the ratio of total distance moved by Chi in total time interval

So here we will have

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d = 500 m = 0.5 km

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so average speed will be 1.5 km/h

4 0
3 years ago
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