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3 years ago

What is the equation of the line that passes through the points (3,8) and (6,2)?

Mathematics

1 answer:

vodka [1.7K]3 years ago

8 0

Answer:

y = −2x+14

plot the points on a graph, and find the slope :)

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Identify whether this equation has one, zero, or

satela [25.4K]

In a bag there are 3 red, 3 yellow, 4 green, and 6 blue marbles. What is the probability of p ( blue ) ?

4 0

3 years ago

I HAVE AN EXAM PLEASE HELP ME GET THE ANSWER

sesenic [268]

Answer: The ladder is 5.3 m long
Step by step solution
1. Draw out the scenario, ie a right triangle where the hypotenuse is the ladder, the wall is 4.5m and the angle the ladder and the ground makes 58 degree.

2. Soh, Cah, Toa
The wall is opposite, the ground is adjacent, and the ladder is hypotenuse
Sine (58) = 4.5/h

3. Solve for hypotenuse
h * sine (58) = 4.5
h = 4.5/sine (58)
h = ~ 5.3 m

3 0

3 years ago

Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex

siniylev [52]

Answer:

$\large \boxed{\sf \ \ \ p=-11 \ \ \ }$

Step-by-step explanation:

Hello,

$\alpha \text{ and } \beta \text{ are the roots of the following equation}$

$2x^2+6x-7=p$

It means that

$2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\$

And we know that

$\alpha= 2\cdot \beta$

So we got two equations

$2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1$

For $\beta =0, \ \ \alpha =0, \ \ p = -7$

For $\beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11$

I assume that we are after two different roots so the solution for p is p=-11

b) $\alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1$

So a quadratic equation with the expected roots is

$x(x-1)=x^2-x$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0

3 years ago

What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17

Pepsi [2]

IQR = 6

First locate the median $Q_{2}$ at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles $Q_{1}$ and $Q_{3}$ located at the centre of the data to the left and right of the median.