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Lady_Fox [76]
3 years ago
14

Find all possible values of b that would make the

Mathematics
1 answer:
RUDIKE [14]3 years ago
4 0
=3*2+bx-6
= 6+bx -6
= 6-6+bx
=0+ bx
B=x
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ss7ja [257]
7.6 x 1/10^5
=7.6 x 1/100,000
=0.000076
4 0
3 years ago
Read 2 more answers
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
A bacteria population is 2000 at time t = 0 and its rate of growth is 1000 · 5t bacteria per hour after t hours. what is the pop
natima [27]

Since you are given the rate of growth, the population must be computed from the integral ...

\displaystyle p(t)=2000+\int_{0}^{t}{\left(1000\cdot 5^{t}\right)}\,dt=2000+\frac{1000}{\ln{(5)}}\cdot \left(5^{t}-1\right)\\\\=2000+\frac{1000}{\ln{(5)}}\cdot 4\approx 4485\qquad\mbox{after 1 hour}

5 0
4 years ago
Solve for x. 12:15 = x:5 4 36 60
bulgar [2K]
4 because 12:15 is 4:5
3 0
3 years ago
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Look at picture and find the value of x please help no links!!
Gelneren [198K]
The best answer to go with is c
8 0
3 years ago
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