

To solve these type of problems you need to use the pythagoras theorem ⇨ Hypotenuse² = Base² + Altitude².
Here,
- Altitude = 1.6 cm.
- Base = 1.2 cm
- Hypotenuse = x
Now, let's solve for x.
Hypotenuse² = Base² + Altitude²
x² = (1.2)² + (1.6)²
x² = 1.44 + 2.56
x² = 4
x = √4
x = <em><u>2</u></em><em><u>.</u></em>
- So, the value of x is <em><u>2</u><u> </u><u>cm.</u></em>
<h3>
<u>NOTE</u><u> </u><u>:</u><u>-</u></h3>
- Pythagoras theorem can be used only in the cases of right-angled triangles. Here, it's given that the triangle is right angled so we can use this theorem.
- To solve the squares if decimals, take them as whole numbers & then just add the decimal points. For example, ⇨ for (1.2)², take it as 12² , then multiply 12 by 12, you'll get 144. Now, add the decimal place accordingly ⇨ 1.44 . So, (1.2)² = 1.44.
4)
the arrow touches the ground when the heigth is 0
so we need to replace h=0 and solve for t

<em>the arrow tuches the ground at 3.4 seconds</em>
5)

replacing

<em>solve for m</em>

<em>the mass is 13.50Kg</em>
<em />
Let the no. of girls be x and boys be y......
x/y=1/3
=>3x=y ...............(I)
now 4 boys leave the class is then
x/y-4=2/5
=>5x=2y-8
(I)=>5x=2(3x)-8
x=8
now 3x=y
=>y=24
therefore no. of girls is 8 and the no. of boy is 24..............
I have tried my best.....hope i helped............