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3 years ago

What is an equation of the line that passes through the points (4, -2) and (8,3)?

1 answer:

4 0

Use the equation to find the slope: m=y2-y1/x2-x1 and plug in each of the y coordinates into the numerator and each of the x coordinates in the denominator

m=-2-3/4-8
-5/-4
m=5/4

Plug in the slope and one of the ordered pairs into y=mx+b. I’ll use (8,3)

3=5/4(8)+b
3=10+b
-7=b

Equation: y=5/4x-7

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Tao wants to check that the expression 3(4x – 6) simplifies to 12x – 18. What is the value when 2 is substituted for x into both

timurjin [86]

Answer:

Step-by-step explanation:

3( 4x - 6)

Let x =2

3( 4*2 -6)

3(8-6)

3*2

Check

12x-18

12*2 -18

24-18

Both equal 6

4 0

3 years ago

Find the absolute mean deviation for this set (-32,9,11,12).<br> A)0<br> B)8<br> C)16<br> D)32

Alex Ar [27]

I think 0 because 9+11+12=32
32+-32 or 32-32= 0

3 0

3 years ago

Read 2 more answers

(x-3)^2/3=4 where x is a real number. provide an exact answer

krek1111 [17]

$\frac{(x-3)^{2}}{3} = 4 \\ (x-3)^{2} = 12 \\ x^{2}-6x+9 = 12 \\ x^{2} -6x-3=0$

The only thing I can think of is using the quadratic formula to solve this one

6 0

3 years ago

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-3(7+2) Distributive Property

V125BC [204]

Answer:

-27

Step-by-step explanation:

-3(7+2)

-3(9)

-27

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3 years ago

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Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). The total sc

Blababa [14]

Using the normal distribution, it is found that the median of the MCAT scores was of 500.9.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

The median is also the 50th percentile, hence, in the normal distribution, it is equals to the mean.

In this problem, the mean score was 500.9, hence the median score was also of 500.9.

You can learn more about the normal distribution at brainly.com/question/24663213

7 0

2 years ago