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3 years ago

Which of the following is not the same as 0.032 liters?

1 answer:

3 0

This question needs the answer choices.

I found these choices for you:
0.00032hL
320cL
32mL

Then you need to make the conversion of 0.032 liters to hectoliters, centiliters and milimilters to check which is not equivalent.

1) 0.032 liters to hectoliters:

 0.032 liter * 1 hectoliter / 100 liter = 0.00032 hecoliter

2) 0.032 liter to centiliters:

 0.032 liter * 100 centiliters / 1 liter = 3.2 centiliter

3) 0.032 liter to mililiter:

 0.032 liter * 1000 mililiter / liter = 32 mililiter

Then, the answer is 320 cL: 320 cL is not the same as 0.032 liters

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What is the volume of 15.2 grams of SO2 at STP?

kiruha [24]

5.512 litres is the volume of 15.2 grams of sulphur dioxide gas at STP.

Explanation:

Data given:

mass of sulphur dioxide = 15.2 grams

conditions is at STP whech means volume = 22.4 litres

atomic mass of sulphur dioxide = 64.06 grams/mole

Number of moles is calculated as:

number of moles = $\frac{mas}{atomic mass of 1 mole}$

Putting the values in the equation:

number of moles = $\frac{15.2}{64.06}$

= 0.23 moles

Assuming that sulphur dioxide behaves as an ideal gas, we can calculate the volume as:

When 1 mole of sulphur dioxide occupies 22.4 litres at STP

Then 0.23 moles of sulphur dioxide occupies 22.4 x 0.23

= 5.152 litres is the volume.

5 0

4 years ago

Nitrogen dioxide is a red-brown gas responsible for the brown color of smog. A container of nitrogen dioxide that is at low pres

____ [38]

Answer:

Initially $1.51\times 10^{-2} moles$ of nitrogen dioxide were in the container .

Explanation:

Volume of the container at low pressure and at room temperature = $V_1=3.4 L$

Number of moles in the container = $n_1$

After more addition of nitrogen gas at the same pressure and temperature.

Volume of the container after addition = $V_2=5.11 L$

Number of moles in the container after addition= $n_2=2.28\times 10^{-2} mol$

Applying Avogadro's law:

$\frac{Volume}{Moles}=constant$ (at constant pressure and temperature)

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

$n_1=\frac{V_1\times n_2}{V_2}=\frac{3.4 L\times 2.28\times 10^{-2} mol}{5.11 L}$

$n_1=1.51\times 10^{-2} mol$

Initially $1.51\times 10^{-2} moles$ of nitrogen dioxide were in the container .

8 0

3 years ago

Consider the following reaction mechanism:

snow_lady [41]

Answer:

Step 2 (the slow step).

Explanation:

The rate-determining step is always the slow step of a mechanism.

That is so, because it is the slow step which limits the reaction.

Imaging that for assembling a toy you have process of three steps:

1. order ten pieces, which you can do in 1 minute: meaning that you can order order the pieces for 60/1 = 60 toys in 1 hour.

2. glue the pieces and hold the toy until the glue hardens, which takes 1 hour: meaning finishingh 1 toy in 1 hour.

3. pack the toy, which takes 2 minutes: meaning that you can pack 60/2 = 30 toys in one hour.

The time to glue and hold one toy until the glue hardens determines that you can assemble 1 toy in 1 hour and not 60 toys or 30 toys.

Thus, the step that determines the rate at which the reaction happens is the slowest step: step 2.

3 0

3 years ago

Read 2 more answers

If you have 2.4L of SO2 gas (at STP) how many moles of sulfur dioxide do you have?

Andru [333]

Answer:

0.107 mole of SO2.

Explanation:

1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).

With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.

This can be obtained as follow:

22.4 L contains 1 mole of SO2.

Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.

Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.

4 0

3 years ago

When 4 moles of aluminum are allowed to react with an excess of chlorine gas, Cl2, how many moles of aluminum chloride are produ

Nat2105 [25]

2Al+3Cl2==>2AlCl3
(4mol Al)(2 mol AlCl3/2 mol Al)=4 mole AlCl3

6 0

4 years ago

Read 2 more answers