Answer:
c
Explanation:
use %composition given to calculate emperical 4mular
Answer:
- Option A) <u><em>Mg + Cl₂ → MgCl₂</em></u>
Explanation:
The law of conservation of mass is guaranteed in a chemical equation. Since the mass of the atoms do not change, that means that the number of each kind of atoms in the reactant side is equal to the number of atoms of the same kind in the product side.
The first equation is:
<em><u>A) Mg + Cl₂ → MgCl₂</u></em>
<u />
Number of atoms:
atom Reactant side Product side
Mg 1 1
Cl 2 2
Therefore, the table displays that there are the same number of atoms of each kind on both sides, showing that<em> the total mass during the chemical reaction stays the same.</em>
<u />
<em><u>B) NaOH + MgCl₂ → NaCl + MgOH</u></em>
This equation displays 2 atoms of Cl on the left side and 1 atom of Cl on the right side; thus, it is not showing that the total mass stays the same during the chemical reaction.
<em />
<u><em>C) 2Na + 2H₂O → NaOH + H₂</em></u>
Neither the sodium, nor oxygen, nor hydrogen atoms are balanced. Thus, this does not show that the total mass stays the same.
<u><em /></u>
<u><em>D) H₂O + O₂ → H₂O</em></u>
The reactant side contains 3 oxygen atoms and the product side contains 1 atoms of oxygen; thus, this is not balanced: it does not show that the total mass stays de same during the chemical reaction.
Answer:
Explanation:
4
N
a
+
O
2
→
2
N
a
2
O
.
By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
61.98
g
⋅
m
o
l
−
1
. If
5
m
o
l
natrium react, then
5
2
m
o
l
×
61.98
g
⋅
m
o
l
−
1
=
154.95
g
natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.
Answer : The freezing point of the solution is, 260.503 K
Solution : Given,
Mass of methanol (solute) = 215 g
Mass of water (solvent) = 1000 g = 1 kg (1 kg = 1000 g)
Freezing depression constant = 
Formula used :
where,
= freezing point of water = 
= freezing point of solution
= freezing point constant
= mass of solute
= mass of solvent
= molar mass of solute
Now put all the given values in the above formula, we get
By rearranging the terms, we get the freezing point of solution.
Therefore, the freezing point of the solution is, 260.503 K
Answer:
The metals that would be able to reduce copper ions in solution would be hydrogen, lead, tin, nickel, iron, zinc, aluminum, magnesium, sodium, calcium, potassium, silver, gold, copper and lithium 5.
Explanation:
