For ideal gases at constant volume, you can use the law of Gay - Lussac:
P / T = constant => P1 / T1 = P2 / T2
=> P2 = T2 * P1 / T1
And remember you have to use absolute scale of temperature.
T1 = 25 + 273.15 = 298.15 K
T2 = 475 + 273.15 = 748.15 K
=> P2 = 748.15 K * 1.8 atm / 298.15 K = 4.5 atm
Answer: 4.5 atm
Answer:

Explanation:
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In this case, since isotopes of the same element have the same number of protons and electrons but different atomic mass, we can compute the number of neutrons by subtracting the number of protons to the atomic mass of the isotope; thus, for Ga-69 and Ga-71 (rounded up to whole numbers), we obtain:

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Answer:
2) 0.109 mol
Explanation:
The density of butan-1-ol is 0.8098g/mL. And its molar mass is: 74.121g/mol.
First, we need to convert volume of butan-1-ol to mass:
10.0mL * (0.8098g / mL) = 8.098g of butan-1-ol
Now, we need to convert these grams to moles using molar mass:
8.098g * (1mol / 74.121g) = 0.109 moles of butan-1-ol
Right answer is:
<h3>2) 0.109 mol
</h3>
Answer:
Explanation:
1.) i would use a scale or a beacon
2.)well beacons are easy you fill them with water and how ever hight the water goes up is the amount of valume the lego or whatever your using has
3.)beacon
4.)you look at the numbers on the side or front derr haha
hope this helped
<h3><u>Answer;</u></h3>
- <u>0.433 g N2 </u>
- <u>0.293 g O2 </u>
- <u>0.0367 g He</u>
<h3><em>Explanation and solution;</em></h3>
- We can start by getting the total pressure; which will be the sum of the partial pressure of each gas.
221 torr + 131 torr + 131 torr
P (total) = 483 torr total
n = PV / RT, we can determine the total number of moles of the mixture
= (483 torr) x (1.30 L) / ((62.36367 L Torr/K mol) x (25.0 + 273.15 K))
= 0.033769 mol gases total
-
Therefore; we can determine the mass of each gas;
- <u>Nitrogen gas </u>
<em>N2 = 28.01 g/mol</em>
<em>= (0.033769 mol) x ( 221 torr N2/ 483 torr) x (28.01 g N2/mol) </em>
<u>= 0.433 g N2 </u>
<em>
O2 = 32 g/ mol </em>
<em> =(0.033769 mol) x (131 torr O2/ 483 torr) x (32 g O2/mol)</em>
<em> </em><em><u>= 0.293 g O2 </u></em>
- <em><u>Helium gas </u></em>
<em><u>
</u></em><em>He = 4 g/mol</em>
<em>= (0.033769 mol) x (131 torr He/ 483 torr) x (4.00 g He/mol) </em>
<em><u>= 0.0367 g He</u></em>