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snow_tiger [21]
3 years ago
9

Given: glow is a find the indicated measure.​

Chemistry
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

is there supposed to be some type of image or ...

Explanation:

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mash [69]

Answer:

ok

Explanation:

pls mark me as brainlist

6 0
3 years ago
Which change in oxidation number represents reduction?
Mrrafil [7]
THE ANSWER IS B. The reducing of oxidation state (-1 to -2, a change of -1, a REDUCTION) is what makes it a reduction.
4 0
3 years ago
Pleaaaaase helppppppppppppp ASAP
laiz [17]

Answer:

Explanation:

a) The forward reaction is exothermic, hence when temperature is increased the equilibrium shift towards the reactants side to get rid of the excess energy. This will mean that more reactants are produced decreasing yield

b) There are a fewer number of moles of gas on the right side compared to the left side (Just count the coefficients before each compound) so a higher pressure will mean that the equilibrium will shift towards the products side in order to decrease the pressure. This will mean that more products are formed increasing yield

c) When something is powdered it's surface area to volume ratio increases. A higher surface area means that the particles around it have more area to work on so the frequency of collisions will increase increasing the rate of reaction. This is why iron is powdered.

4 0
3 years ago
A sexually mature seahorse can produce thousands of offspring. What is the BEST reason overproduction of offspring by marine org
Setler79 [48]
C
the chances of survival is the amount of offsprings the animal has therefore the answer is C.
6 0
3 years ago
Read 2 more answers
A 2.10g of unknown monoprotic acid is titrated with 38.10 mL of .265M NaOH. Calculate the molar mass of the ac? I already calcul
Shkiper50 [21]
V_{NaOH}=38,1mL=0,0381L\\
C_{m}=0,265M\\\\
n=C_{m}*V=0,265\frac{mol}{L}*0,0381L\approx0,0101mol

HR    +      NaOH ⇒ NaR + H₂O
1mol   :     1mol

0,0101mol \ \ \ \ \Rightarrow \ \ \  \ 2,1g\\
1mol  \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ m\\\\
m=\frac{1mol*2,1g}{0,0101mol}\approx 207,92g\\\\
M_{HR}=207,92\frac{g}{mol}
5 0
3 years ago
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