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2 years ago

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Explain why one molecule of nabh4 will reduce only two molecules of m acetylbenzaldehyde to form the corresponding product

1 answer:

Sergeeva-Olga [200]2 years ago

8 0

One molecule of nabh4 will reduce only two molecules of m-acetylbenzaldehyde to form the corresponding product because there are only two functional groups that can react with NaBH4, namely the ketone and the aldehyde, but NaBH4 had four H present to protonate the molecule.

What is protonation?

An atom, molecule, or ion can be protonated by adding a proton to it. The difference between protonation and hydrogenation is that during protonation, the protonated species' charge changes, whereas it remains unchanged during hydrogenation. Numerous catalytic processes result in protonation.

A conjugate acid is created when a proton (or hydron, or hydrogen cation), (H+), is added to an atom, molecule, or ion. Deprotonation is the analogous process that occurs when a proton is taken out of a Bronsted-Lowry acid.

To learn more about protonation click the given link

brainly.com/question/15215343

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$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

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When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be

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Explanation:

The given precipitation reaction will be as follows.

$AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

0.269 M = $\frac{\text{no. of moles}}{1.14 L}$

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No. of moles = $\frac{mass}{\text{molar mass}}$

0.307 mol = $\frac{mass}{143.32 g/mol}$

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