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dlinn [17]
2 years ago
9

Explain why one molecule of nabh4 will reduce only two molecules of m acetylbenzaldehyde to form the corresponding product

Chemistry
1 answer:
Sergeeva-Olga [200]2 years ago
8 0

One molecule of nabh4 will reduce only two molecules of m-acetylbenzaldehyde to form the corresponding product because there are only two functional groups that can react with NaBH4, namely the ketone and the aldehyde, but NaBH4 had four H present to protonate the molecule.

What is protonation?

An atom, molecule, or ion can be protonated by adding a proton to it. The difference between protonation and hydrogenation is that during protonation, the protonated species' charge changes, whereas it remains unchanged during hydrogenation. Numerous catalytic processes result in protonation.

A conjugate acid is created when a proton (or hydron, or hydrogen cation), (H+), is added to an atom, molecule, or ion. Deprotonation is the analogous process that occurs when a proton is taken out of a Bronsted-Lowry acid.

To learn more about protonation click the given link

brainly.com/question/15215343

#SPJ4

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Consider the reaction below 2SO2(g) + O2(g) ⇌ 2SO3(g) At 1000 K the equilibrium pressures of the three gases in one mixture were
Vsevolod [243]

Answer:K_p for the reaction is 3.45

Explanation:

The balanced chemical reaction is:

          2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)                  

At eqm.   0.562 atm   0.101 atm    0.332 atm

As we are given that:

The expression of K_p for above equation follows:

K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times p_{O_2}}

Putting values in above equation, we get:

K_p=\frac{(0.332)^2}{(0.562)^2\times 0.101}=3.45

The value of K_p for the reaction is 3.45

8 0
3 years ago
What is the smallest metal atom size with p electrons?
konstantin123 [22]
<h2><u>Answer:</u></h2>

Component having Smallest Atomic Size is 'Helium' having range approx. 31pm  

I have seen that numerous individuals are noting with respect to hydrogen Atom however the genuine reason is along a period (left to right) the nuclear number increments while the valence electrons stay in a similar shell. Along these lines because of the expanding atomic charge (pulling electrons closer to the core) the radii of the iotas decline left to right.  

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3 years ago
Boyle's Law expresses the pressure-volume
Colt1911 [192]

Answer:

\large \boxed{\text{175. atm}}

Explanation:

Data:

p₁ = 1.00 atm; V₁ = 350.      L

p₂ = ?;             V₂ =     2.00 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{1.00 atm} \times \text{350. L} & = & p_{2} \times\text{2.00 L}\\\text{350. atm} & = & 2.00p_{2}\\p_{2} & = & \dfrac{\text{350. atm}}{2.00}\\\\& = &\textbf{175. atm}\\\end{array}\\\text{It would take a pressure of $\large \boxed{\textbf{175. atm}}$ to compress the gas.}

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3 years ago
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makvit [3.9K]

Answer:

48 N

Explanation:

f=ma (from Newton's second law of motion)

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2 years ago
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