How much pressure (in atm) would be found in 5.8 moles of an ideal gas at 358 K and volume of 3.9 L?
1 answer:
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Answer:
Rate of formation of SO₃ = 7.28 x 10⁻³ M/s
Explanation:
According to equation 2 SO₂(g) + O₂(g) → 2 SO₃(g)
Rate of disappearance of reactants = rate of appearance of products
⇒ -----------------------------(1)
Given that the rate of disappearance of oxygen = = 3.64 x 10⁻³ M/s
So the rate of formation of SO₃ = ?
from equation (1) we can write
⇒ = 2 x 3.64 x 10⁻³ M/s
⇒ = 7.28 x 10⁻³ M/s
∴ So the rate of formation of SO₃ = 7.28 x 10⁻³ M/s