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Svetradugi [14.3K]
3 years ago
14

PLEASE I NEED HELP WITH MY MATH!!

Mathematics
1 answer:
kati45 [8]3 years ago
3 0

Answer:

I do not know that does not look like it is equivalent.

Step-by-step explanation:

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4(b+c)-m(b+c)\\\\=(b+c)(4-m)

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Please help with this problem
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B

Step-by-step explanation:

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Shawna reduced the size of a rectangle to a height of 2 in. What is the new width if it was originally 24 in wide and 12 in tall
miskamm [114]

Answer:

4 inches.

Step-by-step explanation:

The height of a rectangle is reduced by Shawna to a size of 2 inches.

The original width of the rectangle was 24 inches and the height was 12 inches.

If the ratio of width to height remains the same, then we can find the new width.

If the new width is x inches then, we can write

\frac{x}{2} = \frac{24}{12}

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Find the Taylor series for f(x)=sin(x) centered at c=π/2.sin(x)=∑ n=0 [infinity]On what interval is the expansion valid? Give yo
agasfer [191]

Answer:

sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...

Step-by-step explanation:

given that f(x) = sin x

we have to find the Taylor series for that

f(x) = sin x   : f( = 1\\f'(x) = cos x :(f'\frac{\pi}{2})=0\\f"(x) = -sinx :f" (\frac{\pi}{2}) =-1\\f^4 (x) = -cosx : f^4 (\frac{\pi}{2}) =0

and so on.

i.e. 2nd, 4th, 6th terms would be 0

and also 1st, 5th, 9th terms would be positive for f value and 3rd, 9th,... would be negative

Using the above we can write Taylor series as

f(x) = f(a)+\frac{f'(a)}{1!} (x-\frac{\pi}{2}) +...+f^n(a) /n! (x- \frac{\pi}{2})^n+...

sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...

This is valid for all real values of x.

x ∈(-\infty, infty)

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3 years ago
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liberstina [14]

Answer:

Hexagon and rectangle

Step-by-step explanation:

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