(y^2)^5 *y^8 = y^10 *y^8 = y^18
hope this will help you
Chileeeeeeeeeeeeeeeeeeeeeeeeeee
Following changes are made in graph of G(x) to obtain F(x)
1) Vertical stretch by a factor of 2
So, G(x) will be changed to 2G(x)
2) Shift towards Right by 2 units
So, 2G(x) will be changed to 2G(x - 2)
3) Upward shift by 2 units.
So, 2G(x - 2) will be changed to 2G(x - 2) + 2
Thus,
F(x) = 2G(x - 2) + 2
F(x) = 2(x - 2)² + 2
Therefore, option C is the correct answer
Answer:
While factoring may not always be successful, the Quadratic Formula can always find the solution. The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.
source from: https://www.purplemath.com/modules/quadform.htm
your welcome!
Henry has 3 / 4 0f total cost so,
Let ( a ) is total cost of game
So,
3/4 × a = total cost
12 = 3/ 4 × a
4 will multiply with 12 so,
12 x 4 = 3 a
48 = 3a
48 / 3= a
16 = a will be price of game
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