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Rzqust [24]
3 years ago
10

Solve for t.

Mathematics
1 answer:
Greeley [361]3 years ago
6 0
The answer is 5. Hope this helps
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The fare for a taxi cab is $2.50 per passenger and $0.75 for each mile. A group of friends has $22.00
xeze [42]

For this case we have to:

x: Let the variable representing the number of people to travel in the group

y: Let the variable representing the number of miles traveled.

If friends only have $22 then we have the following inequality:

2.50x + 0.75y \leq22

Now, if there are three people in the group we have that x = 3.

2.50 (3) + 0.75y \leq22\\7.5 + 0.75y \leq22\\0.75y \leq22-7.5\\0.75y \leq14.5\\y\leq \frac {14.5} {0.75}\\y\leq19.33

The taxi can travel a maximum of 19.33 miles.

On the other hand, if the group wants to travel 10 miles then we have to y = 10.

2.50x + 0.75 (10) \leq22\\2.50x + 7.5 \leq22\\2.50x \leq22-7.5\\2.50x \leq14.5\\x\leq \frac {14.5} {2.50}\\x \leq5.8

Thus, they could travel a maximum of 5 people.

ANswer:

2.50x + 0.75y \leq22

Traveling 3 people, the taxi can travel a maximum of 19.33 miles

Traveling 10 miles, a maximum of 5 people can travel

7 0
3 years ago
What is the solution to -4 | -2x +6 | = -24
Norma-Jean [14]

Answer:

please ignore my answer

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to (3-5x)(3+5x)​
Levart [38]
I think the answer is 9-25x
5 0
3 years ago
HELP HELP HELP I WILL GIVE BRAINLIEST YALL BETTER NOT GIVE ME A NOT SMART ANSWERS IF YOU DO ILL REPORT THE QUESTION :/
monitta

Answer:

C

Step-by-step explanation:

Multiply ben (y) by 4 since dave has 4x more and add % since jeff has 5 more than Daves total

Hope this helps ^_^

5 0
2 years ago
A distribution is given as
Arada [10]

If <em>X</em> is uniformly distributed on the interval (0, 12), then its PDF is

f_X(x) = \begin{cases}\frac1{12} & \text{if }0 < x < 12 \\ 0&\text{otherwise}\end{cases}

or simply

f_X(x) = \dfrac1{12} \text{ where } 0 < x < 12

and the zero-elsewhere case is assumed.

Whether you include 0 and 12 in the domain is irrelevant, since the probability that <em>X</em> = 0 or <em>X</em> = 12 are both zero.

4 0
2 years ago
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