Answer:Choice A) All points with an x-value of 3 are located in Quadrant I.
We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.
We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.
Answer:
Using the visual, 20 blocks, but you still need to change it to match the problem's scale
Step-by-step explanation:
First just try to find a way out and count the blocks. That's what I did. The part I haven't done is scale it. As the starting and end points of the grid are given, but where they fall is not clear, I don't know what the block to number ratio is. Sorry, maybe ask a teacher, they shouldn't take off any points.
You first need to find the LCD (lowest common denominator). You will need to find the smallest number that is a multiple of all numbers that is the denominator (2, 16, 8). Or, to say it another way, all the numbers in the denominator need to be a factor of this number.
You can find this by first checking if the largest number that is the denominator-- in this case 16-- is already the LCD, which means 16 is divisible by all the other numbers.
If this does not work, then multiply all the numbers together to get the LCD-- since you multiplied them together, you know that they will all be factors of the product.
However, you will be able to see that 16 is indeed the lowest common denominator:
2 × 8=16
8 × 2=16
16 × 1=16
So, after you find the LCD, multiply both the numerator and the denominator by the number that you would need to multiply the denominator to get the LCD (the whole point is that you want to get the denominator to be the LCD, but to do that you need to multiply both the top and bottom by the same number to keep the fraction the same).
(1/2) x (8/8)= 8/16
(3/16) x (1/1)= 3/16
(7/8) x (2/2)= 14/16
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