What is the area of a rectangular garden that is 60 feet by 20 feet

The pH of lemon juice at 298 K is found to be 2. 32. What is the concentration of mc014-1. Jpg ions in the solution? Use StartBr

sdas [7]

The concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.

<h3>What is pH value?</h3>

The pH value shows that how much a solution is acidic or basic. The range of the pH value lies between the 0-14.

The pH value can be calculated with the following formula.

$\rm pH=log[H^{+}]$

Here, [H⁺] is the molar hydrogen ion concentration.

The pH of lemon juice at 298 K is found to be 2. 32. Put this value of pH in the above formula as,

$\rm 2.32=log[H^{+}]\\\ [H^{+}]=4.79\times10^{-3} \rm \; M$

Hence, the concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.

Learn more about the pH value here;

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8 0

2 years ago

Which property is illustrated by the statement<br> (2+3.4)+6=2+(3.4+6)

aleksandrvk [35]

Answer:

Associative property is illustrated.

Step-by-step explanation:

we have been given:

(2+3.4)+6=2+(3.4+6)

This is the associative identity which is:

a+(b+c)=(a+b)+c

Here, we have a=2, b=3.4, c=6

On comparing the values with associative property we get:

(2+3.4)+6=2+(3.4+6)

We club two numbers b and c first and then a and b in same bracket.

6 0

3 years ago

Read 2 more answers

A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and

natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: $E=k\frac{q}{r^{2} }$ ; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: $p=\frac{q}{A}$ ; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: $S=4\pi r^{2}$ ; which gives us the surface of a sphere.