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just olya [345]
3 years ago
5

what is the molarity of an HCI solution if 25.0 ml of 0.185 M NaOH is required to neutralize 0.0200 L of HCI?​

Chemistry
1 answer:
butalik [34]3 years ago
7 0

Answer:

Molarity of HCl solution = 0.25 M

Explanation:

Given data:

Volume of NaOH= V₁ = 25.0 mL (25/1000 = 0.025 L)

Molarity of NaOH solution=M₁ = 0.185 M

Volume of HCl solution = V₂ = 0.0200 L

Molarity of HCl solution =  M₂= ?

Solution:

M₁V₁   =  M₂V₂

0.185 M ×0.025 L =  M₂ × 0.0200 L

M₂  = 0.185 M ×0.025 L / 0.0200 L

M₂  = 0.005M.L /0.0200 L

M₂  =  0.25 M

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Answer:

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Carbon-14 has a half-life of approximately 5700 years. How much of a 1000g sample will be left undecayed and still radioactive a
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Answer:

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Explanation:

Given data:

Half life of carbon-14 = 5700 years

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Sample left after 11,400 years = ?

Solution:

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Number of half lives = time elapsed/ half life

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Number of half lives = 2

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4 0
3 years ago
How many liters of solution would it take to make a 0.250 M solution when you have 3.52 moles of solute?
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Answer:

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Explanation:

The question relates to the definition of the concentration of a solution which is the number of moles per liter (1 liter = 1 dm³) of solution

Therefore we have;

The concentration of the intended solution = 0.250 M

Therefore, the number of moles per liter of the required resolution = 0.250 moles

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The volume in liters of the required solution that will have 3.52 moles of the solute is given as follows;

The required volume of solution = The number of moles of the solute/(The concentration of the solution)

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The required volume of solution to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

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8 0
3 years ago
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The statement of the combined gas law for a fixed amount of gas is,
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8 0
4 years ago
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