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just olya [345]
3 years ago
5

what is the molarity of an HCI solution if 25.0 ml of 0.185 M NaOH is required to neutralize 0.0200 L of HCI?​

Chemistry
1 answer:
butalik [34]3 years ago
7 0

Answer:

Molarity of HCl solution = 0.25 M

Explanation:

Given data:

Volume of NaOH= V₁ = 25.0 mL (25/1000 = 0.025 L)

Molarity of NaOH solution=M₁ = 0.185 M

Volume of HCl solution = V₂ = 0.0200 L

Molarity of HCl solution =  M₂= ?

Solution:

M₁V₁   =  M₂V₂

0.185 M ×0.025 L =  M₂ × 0.0200 L

M₂  = 0.185 M ×0.025 L / 0.0200 L

M₂  = 0.005M.L /0.0200 L

M₂  =  0.25 M

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3 years ago
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What mass of radon is in 8.17 moles of radon?
Len [333]

Answer:

1813.74g

Explanation:

Given parameters:

Number of moles of radon  = 8.17moles

Unknown:

Mass of radon  = ?

Solution:

To solve this problem, we use the expression below:

      Number of moles = \frac{mass}{molar mass}  

Molar mass of radon  = 222g/mol

Now insert the parameters and solve;

    Mass of radon  = Number of moles x molar mass

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3 years ago
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A graduated cylinder

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2 years ago
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Balancing Chemical Equations Worksheet
Goshia [24]

The balanced chemical equation of the reactions given is as follows:

  • 2LiHCO3 -----> Li2CO3 + H2O + CO2
  • 2 N2 + 5 O2 -----> 2 N2O5
  • MgBr2 + KOH -----> KBr + Mg(OH)2
  • Mn + 2 CuCl -----> 2 Cu + MnCl2
  • 8 Zn + S8 -----> 8 ZnS
  • 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
  • 2 K + 2 H2O -----> 2 KOH + H2
  • C5H12 + 8 O2 -----> 6H2O + 5 CO2
  • 2 KOH + H2CO3 -----> 2 H2O + K2CO3
  • C4H802 + 6 O2 -----> 4 H20 + 4 CO2
  • 16 Al + 3 S8 ---> 8 Al2S3

<h3>How to balance chemical equations</h3>

Balancing of chemical equations is the process of adding numerical coefficients in front of moles of reactants and products to ensure that the moles of atoms of elements of the reactants is equal to the moles of atoms of products formed.

The balanced chemical equation of the reactions given is as follows:

  • 2LiHCO3 -----> Li2CO3 + H2O + CO2
  • 2 N2 + 5 O2 -----> 2 N2O5
  • MgBr2 + KOH -----> KBr + Mg(OH)2
  • Mn + 2 CuCl -----> 2 Cu + MnCl2
  • 8 Zn + S8 -----> 8 ZnS
  • 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
  • 2 K + 2 H2O -----> 2 KOH + H2
  • C5H12 + 8 O2 -----> 6H2O + 5 CO2
  • 2 KOH + H2CO3 -----> 2 H2O + K2CO3
  • C4H802 + 6 O2 -----> 4 H20 + 4 CO2
  • 16 Al + 3 S8 ---> 8 Al2S3

Learn more about balancing of chemical equations at: brainly.com/question/15428811

5 0
3 years ago
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