Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.
Explanation:
density
ρ
=
Mass
Volume
, and thus units of
g
⋅
m
L
−
1
are reasonable.
For this problem:
17.4
⋅
m
L
×
0.798
⋅
g
⋅
m
L
−
1
≅
14
⋅
g
but A i supposed?
Answer:
The soil has a percentage of water by mass of 27.8 %.
Explanation:
Keeping in mind that
- Mass of Clay = Mass of water + Mass of Dry Soil
we can <u>calculate the mass of water</u>:
- 1350 g = Mass of Water + 975 g
We can then <u>calculate the mass percentage of water in the soil</u>:
- 375 / 1350 * 100% = 27.8 %
Answer:
56.0 g
Explanation:
Calculation of the moles of 
as:-
Mass = 85.0 g
Molar mass of = 162.2 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the reaction:-
1 mole of on reaction forms 1 mole of 
Also,
0.52404 mole of on reaction forms 0.52404 mole of
Moles of = 0.52404 moles
Molar mass of = 106.867 g/mol
Mass = Moles*Molar mass = 
= 56.0 g
